Answer:
–500KJ
Explanation:
Data obtained from the question include the following:
Heat of reactant (Hr) = 800KJ
Heat of product (Hp) = 300KJ
Enthalphy change (ΔH) =..?
The enthalphy change is simply defined as the difference between the heat of product and the heat of reactant i.e
Enthalphy change = Heat of product – Heat of reactant
ΔH = Hp – Hr
With the above formula, we can easily calculate the enthalphy change as follow
ΔH = Hp – Hr
ΔH = 300 – 800
ΔH = –500KJ.
Therefore, the overall energy change for the reaction between hydrogen and oxygen shown in the diagram above is –500KJ
Answer:
The periodic table is composed of seven horizontal rows or periods and is numbered between 1 and 7. There is a regular gradation in the properties of elements in the horizontal rows(periods) from left to right. The periodic table is composed of eight vertical columns or groups. They are numbered between 1 to 8.
Explanation:
<em>Sulphur </em><em>Trioxide</em><em> </em><em>=</em><em> </em><em>So</em><em>3</em>
<em>Sodium</em><em> Hydroxide</em><em> </em><em>=</em><em> </em><em>NaoH</em>
Answer:
The answer to your question is -2855 J
Explanation:
Reaction
2C₂H₆ + 7O₂ ⇒ 4CO₂ + 6H₂O
Formula
Heat of reaction = ΔHrxn = ΣΔHrxn products - ΣΔHrxn reactants
Substitution
ΔHrxn = { 4(-393.5) + 6(-241.8)} - {2(-84.7) + 7(0)}
ΔHrxn = {-1574 -1450.8} - {-169.4}
ΔHrxn = -3024.8 + 169.4
ΔHrxn = -2855.4 J
1 liter= 1,000,000 microliters
20 mL= 20,000 microliter
I hope this helped ;)))
