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4 years ago

6

Ampere second could be the unit of : O power O conductance O energy O charge

1 answer:

ASHA 777 [7]4 years ago

8 0

Answer:

Charge

Explanation:

Unit of ampere is defined as the coulomb of charge per unit time which is in seconds.

$i=\frac{q}{t}$

Here, i is in ampere, qis the charge which is in coulomb, and the t is in sec which is time.

Therefore,

$q=it$

Charge=ampere-second.

Therefore, the unit ampere-second will represent the charge.

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A proton has a speed of 3.50 Ã 105 m/s when at a point where the potential is +100 V. Later, itâs at a point where the potential

ruslelena [56]

Answer:

(a). The change in the protons electric potential is 0.639 kV.

(b). The change in the potential energy of the proton is $1.022\times10^{-16}\ J$

(c). The work done on the proton is $-8\times10^{-18}\ J$ .

Explanation:

Given that,

Speed $v= 3.50\times10^{5}\ m/s$

Initial potential V=100 V

Final potential = 150 V

(a). We need to calculate the change in the protons electric potential

Potential energy of the proton is

$U=qV=eV$

Using conservation of energy

$K_{i}+U_{i}=K_{f}+U_{f}$

$\dfrac{1}{2}mv_{i}^2+eV_{i}=\dfrac{1}{2}mv_{f}^2+eV_{f}$

$]\dfrac{1}{2}mv_{i}^2-]\dfrac{1}{2}mv_{f}^2=e(V_{f}-V_{i})$

$\dfrac{1}{2}mv_{i}^2-]\dfrac{1}{2}mv_{f}^2=e\Delta V$

$\Delta V=\dfrac{m(v_{i}^2-v_{f}^2)}{2e}$

Put the value into the formula

$\Delta V=\dfrac{1.67\times10^{-27}(3.50\times10^{5}-0)^2}{2\times1.6\times10^{-19}}$

$\Delta V=639.2=0.639\ kV$

(b). We need to calculate the change in the potential energy of the proton

Using formula of potential energy

$\Delta U=q\Delta V$

Put the value into the formula

$\Delta U=1.6\times10^{-19}\times639.2$

$\Delta U=1.022\times10^{-16}\ J$

(c). We need to calculate the work done on the proton

Using formula of work done

$\Delta U=-W$

$W=q(V_{2}-V_{1})$

$W=-1.6\times10^{-19}(150-100)$

$W=-8\times10^{-18}\ J$

Hence, (a). The change in the protons electric potential is 0.639 kV.

(b). The change in the potential energy of the proton is $1.022\times10^{-16}\ J$

(c). The work done on the proton is $-8\times10^{-18}\ J$ .

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The greatest ocean depths on the Earth are found in the Marianas Trench near the Philippines. Calculate the pressure (in atm) du

frozen [14]

Answer:

$P = 103867260$ atm

Explanation:

The pressure at the bottom of any liquid column is equal to product of density of the liquid , gravitational acceleration constant (g) and height of the water column

Thus, $P = \rho*g*h$

Substituting the given values, we get -

$P = 1029$ kg/m3 $* 9.8$ m/s^2 $*10.3 *1000$ meters

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3 years ago

If one mile is 5280 feet, how many inches are in 3.94 km?

Yakvenalex [24]

Answer:

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Explanation:

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2 years ago

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Anastaziya [24]

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Since the equation for Work is as follows....

Work = Force x Displacement

Your equation is...

Work = 300N x 15m

Work = 4,500 Joules

8 0

4 years ago