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kati45 [8]
3 years ago
6

Which of the following statements are true?

Physics
2 answers:
daser333 [38]3 years ago
5 0

Answer:

A voltmeter is used to measure voltage.

An voltmeter must be placed in parallel with a resistor to measure the voltage through the resistor.

An ammeter is used to measure current.

Explanation:

Voltmeter measures the voltage difference between two different points as connected in parallel not change the amount of current going through the element between those two points. So, an ideal voltmeter has very high resistance so that it doesn't "draw" current through it i.e loading effect.

Ammeter has almost negligible or very small resistance. As a result, it must be connected in series so that as much current can pass through it as possible. If it is connected in parallel, the circuit will be shorted and no current will pass through any electrical components connected in the circuit.

ale4655 [162]3 years ago
4 0

Answer:

A) True. Voltmeters measure voltages

C) True. They are placed in parallel

E) True ammeters are used to measure current

Explanation:

The devices for voltage measurement are the voltmeter and ammeter

Voltmeters have very high intense resistance and are placed in parallel

The ammeters have very small resist and are placed in series

Based on this establishment, let's analyze the statements

A) True. Voltmeters measure voltages

B) False has high intense resistance

C) True. They are placed in parallel

D) False ammeters are placed in series

E) True ammeters are used to measure current

F) False ammeters have a low internal resistance

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Explanation:

By frequency of its rotation and the radius of the circular path along which objects moves

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A balloon filled with helium gas at 20°C occupies 4.91 L at 1.00 atm. The balloon is immersed in liquid nitrogen at -196°C, whil
Marizza181 [45]

Answer:

V = 0.248 L

Explanation:

To do this, use the following equation:

P1*V1/T1 = P2*V2/T2

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Solving for V2:

V2 = P1*V1*T2/T1*P2

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7 0
3 years ago
HELP ;
mestny [16]

Answer:

The frequency would double.

Explanation:

Given:

Speed of wave (v) = constant.

Frequency of wave initially (f₁) = 2 Hz

Initial wavelength of the wave (λ₁) = 1 m

Final wavelength of the wave (λ₂) = 0.5 m

Final frequency of the wave (f₂) = ?

We know that the product of wavelength and frequency of the wave is equal to the speed of the wave.

Therefore, framing in equation form, we have:

Wavelength × Frequency = Speed

\lambda\times f=v

It is given that speed of the wave remains the same. So, the product must always be a constant.

Therefore,

\lambda\times f=constant\ or\ \\\lambda_1\times f_1=\lambda_2\times f_2

Now, plug in the given values and solve for 'f₂'. This gives,

1\times 2=0.5\times f_2\\\\f_2=\frac{2}{0.5}=4\ Hz

Therefore, the final frequency is 4 Hz which is double of the initial frequency.

f₂ = 2f₁ = 2 × 2 = 4 Hz

So, the second option is correct.

7 0
4 years ago
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How is capacitance related to the distance between the plates of a capacitor?
svetlana [45]

Answer:C

Explanation: I studied, and C is correct

5 0
3 years ago
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