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bonufazy [111]
2 years ago
10

What is the mass of a 2.5 mole sample of MgO2

Chemistry
1 answer:
MrRa [10]2 years ago
6 0
Mass = no. of moles x molecular weight
m = n x Mr
m = 2.5 mol x (24 + [16 x 2])
m = 140g
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Water has a density of 1g/ml. what is the mass of the water if it fills a 10ml container?
notka56 [123]
It's 10.
Mass = density x volume
M = 1g/ml(10ml) = 10g
8 0
2 years ago
Read 2 more answers
Mars is known as the ____ planet.<br><br> A) Blue<br> B) Gaseous<br> C) Red<br> D) Sandy
Leni [432]

Answer:

Of course it's C

Red planet

Explanation:

It is because the soil on Mars is rich of Fe (Iron).

That makes the soil look red.

Even on our planet we have such this places like hormuz island in Iran.

5 0
3 years ago
Silver metal can be prepared by reducing its nitrate, AgNO3 with copper according to the following equation:
Lerok [7]

%yield = 88.5%

<h3>Further explanation</h3>

Given

Reaction

Cu(s) + 2 AgNO₃(aq) → Cu(NO₃)₂(aq) + 2Ag(s)

Required

The percent yield

Solution

mol AgNO₃(MW=169,87 g/mol) :

= mass : MW

= 127 : 169.87

= 0.748

mol Ag from equation :

= 2/2 x mol AgNO₃

= 2/2 x 0.748

= 0.748

Mass Ag (theoretical) :

= mol x Ar Ag

= 0.748 x 108

= 80.784

% yield = (actual/theoretical) x 100%

%yield = 71.5/80.784 x 100%

<em>%yield = 88.5%</em>

7 0
2 years ago
g Write a molecular equation for the precipitation reaction that occurs (if any) when the following solutions are mixed. If no r
Mrac [35]

Answer:

CuBr₂(aq) + Pb(CH₃COO)₂(aq) → Cu(CH₃COO)₂(aq) + PbBr₂ (s)↓

Explanation:

We identify the reactants:

CuBr₂ and Pb(CH₃COO)₂

The products will be: Cu(CH₃COO)₂ and PbBr₂

You may know these information:

Salts from acetate are soluble.

Bromide can make solid salts with these cations: Ag⁺, Pb²⁺, Hg₂²⁺, Cu⁺

PbBr₂ is formed, so this will be our precipitate

The equation is:

CuBr₂(aq) + Pb(CH₃COO)₂(aq) → Cu(CH₃COO)₂(aq) + PbBr₂ (s)↓

8 0
2 years ago
What is the percent by mass of oxygen in carbon dioxide (CO2)?
wariber [46]

Answer:

= 72.73%

Explanation:

The percentage by mass of an element is given by;

% element = total mass of element in compounds/molar mass of compound × 100

The mass of oxygen in carbon dioxide = 32 g

Molar mass of CO2 = 44 g

Therefore;

% of O2 = 32/44 × 100%

             <u>= 72.73%</u>

8 0
3 years ago
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