Create the Lewis structure of CF4. NOTE: do only the step asked for in each part and then click Check–don't work ahead to solve
the final structure.
Step 1. Count valence electrons in the molecule or ion. Do this by adding the periodic group numbers for each atom in the structure and adjusting for charge. Enter and Check.
Step 1. Count valence electrons in the molecule or ion. Do this by adding the periodic group numbers for each atom in the structure and adjusting for charge. Enter and Check.
1 answer:
To create the Lewis structure we need to take into account the octet rule: atoms tend to gain, lose or share electrons to complete their valence shell with 8 electrons.
C belongs to Group 4A in the periodic table so it has 4 valence electrons. It needs to share 4 pairs of electrons to complete the octet.
F belongs to Group 7A in the periodic table so it has 7 valence electrons. Each F needs to share 1 pair of electrons to complete the octet.
As a consequence, in CF₄, C will form a single bond with each F and all the octets will be complete.
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Answer:
The anode made of the impure copper
The cathode made of pure copper
The electrolyte of copper (II) sulfate CuSO₄ solution
The silver impurities at the anode due to their high tendency of accepting electrons and being a stronger reducing agent than either copper or zinc will remain relatively in place and relatively stable and will not actively take part in the oxidation reaction taking place at the anode
The zinc impurities will be the first element of the three metals to give up electrons and go into the solution as zinc ions due to their high tendency to loan out two electrons and become oxidized into Zn²⁺ ions
The drawing of the electrolytic cell created with Microsoft Visio is attached
Explanation:
