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masya89 [10]
4 years ago
12

An astronaut standing on a platform on the moon drops a hammer. if the hammer falls 6.0 meters vertically in 2.7 seconds, what i

s its acceleration?
Physics
1 answer:
Amanda [17]4 years ago
4 0
The distance that is traveled by the astronaut given that the motion is free-fall can be calculated through the equation,

    d = Vot + 0.5at²

where d is the distance, Vo is the initial velocity, t is the time, and a is the acceleration. Substituting the known,

   6 = (0 m/s)(2.7 s) + 0.5(a)(2.7 s)²

Determining the value of a,
    a = 1.646 m/s²

ANSWER: 1.646 m/s²
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Defination of radiation​
saw5 [17]

Answer:

the emission of energy as electromagnetic waves or as moving subatomic particles, especially high-energy particles which cause ionization.

Explanation:

6 0
3 years ago
Read 2 more answers
What pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c?
Ronch [10]

The pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.

Therefore, option A is correct option.

Given,

Mass m = 14g

Volume= 3.5L

Temperature T= 75+273 = 348 K

Molar mass of CO = 28g/mol

Universal gas constant R= 0.082057L

Number of moles in 14 g of CO is

n= mass/ molar mass

= 14/28

= 0.5 mol

As we know that

PV= nRT

P × 3.5 = 0.5 × 0.082057 × 348

P × 3.5 = 14.277

P = 14.277/3.5

P = 4.0794 atm

P = 4.1 atm.

Thus we concluded that the pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.

learn more about pressure:

brainly.com/question/22613963

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5 0
1 year ago
If a 0.75 efficient motor produces 150 W of useful power, what was the input power? *
vlada-n [284]

Answer:

<em>The input power is 200 W</em>

Explanation:

<u>Motor Efficiency</u>

The efficiency of a motor can be calculated as follows:

\displaystyle \beta=\frac{P_o}{P_i}

Where:

β   = efficiency

Po = Output power

Pi  = Input power

Solving for Pi:

\displaystyle P_i=\frac{P_o}{\beta}

The efficiency is β=0.75 and the output power is Po=150 W, thus the input power is:

\displaystyle P_i=\frac{150}{0.75}

P_i=200 \ W

The input power is 200 W

4 0
3 years ago
If you are driving 90 km/hkm/h along a straight road and you look to the side for 2.2 ss , how far do you travel during this ina
ICE Princess25 [194]

Answer: 55m

Explanation:

Given the following :

Driving speed = 90km/hr

Inattentive period (time) = 2.2s

Distance during inattentive period =

(driving speed * time)

Converting driving speed from km/hr to m/s

1000m = 1km

3600s = 1hour

Therefore,

90km/hr = (90 * 1000) / 3600

90km/hr = (90000)/ 3600 = 25m/s

Therefore ;

Distance during inattentive period =

(driving speed * time)

Distance during inattentive period = (25m/s × 2.2s) = 55m

Distance traveled during inattentive period is 55m

6 0
3 years ago
If our solar system's Sun was half the mass as it is now, what would happen to the orbit of the Earth
avanturin [10]
Essentially, an increase in mass means an increase in gravity, while a decrease in mass means a decrease in gravity. So if the Sun spontaneously lost half its mass (gasp, shudder, the horror!) then its gravitational pull on Earth would lessen as well, ultimately changing the very nature of our orbit around the Sun.
Thank You!
Please Mark Brainliest!
5 0
3 years ago
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