The answer is D hope this helps
Let <em>a</em> denote the airplane's velocity in the air, <em>g</em> its velocity on the ground, and <em>w</em> the velocity of the wind. (Note that these are vectors.) Then
<em>a</em> = <em>g</em> + <em>w</em>
and we're given
<em>a</em> = (325 m/s) <em>j</em>
<em>w</em> = (55.0 m/s) <em>i</em>
Then
<em>g</em> = - (55.0 m/s) <em>i</em> + (325 m/s) <em>j</em>
The ground speed is the magnitude of this vector:
||<em>g</em>|| = √[ (-55.0 m/s)² + (325 m/s)² ] ≈ 330. m/s
which is faster than the air speed, which is ||<em>a</em>|| = 325 m/s.
