All categories

3 years ago

20) If there was no gravity, what would happen to a moving object? Which law is this? 21) What factors are included in gravity

1 answer:

3 0

20) a moving object would still move but it would also float since no pressure is holding it down.
21) The amount of mass determines the gravitational pull, the more the mass the greater the pull.

You might be interested in

What controls the frequency of a wave?

sashaice [31]

Answer:

Wave frequency can be measured by counting the number of crests (high points) of waves that pass the fixed point in 1 second or some other time period. The higher the number is, the greater the frequency of the waves. ... For example, it is the distance between two adjacent crests in the transverse waves in the diagram.

Explanation:

4 0

3 years ago

I need help !!!!! Show the work plz!!!!

horrorfan [7]

Answer:

26) 2 meters a second

27) 2 meters a second

28) 5 meters a second

29) 8 km

Explanation:

1/.5 =2

8/4=2

50/10=5

8km×1= 8

7 0

3 years ago

The density of a substance is 3.4 g cm-3. Its relative density relative to another substance is 2.0. what is the density of the

ankoles [38]

Answer:

1.7 g/cm³

Explanation:

Given that:

Density of substance = 3.4 g/cm³

Relative density to another substance = 2

Density of second substance=?

Let density of second substance = x

Relative density = density of substance / density of second substance

Relative density = density of substance / x

2.0 = 3.4g/cm³ / x

2 * x = 3.4 g /cm³

x = 3.4 g/cm³ ÷ 2

x = 1.7 g/cm³

5 0

3 years ago

Please I need it now

Nana76 [90]

1. A vector $\vec x$ is a unit vector if its magnitude is 1. Given

$\vec A = \dfrac{\sqrt3}2\,\vec\imath - \dfrac12\,\vec\jmath \\\\ \vec B = -\dfrac{\sqrt2}2\,\vec\imath - \dfrac{\sqrt2}2\,\vec\jmath \\\\ \vec C = \dfrac12\,\vec\imath - \dfrac{\sqrt3}2\,\vec\jmath - \dfrac12\,\vec k$

$\vec A$ and $\vec B$ are unit vectors, while $\vec C$ is not, since

$\|\vec A\| = \sqrt{\left(\dfrac{\sqrt3}2\right)^2 + \left(-\dfrac12\right)^2} = 1 \\\\ \|\vec B\| = \sqrt{\left(-\dfrac{\sqrt2}2\right)^2 + \left(-\dfrac{\sqrt2}2\right)^2} = 1 \\\\ \|\vec C\| = \sqrt{\left(\dfrac12\right)^2+\left(-\dfrac{\sqrt3}2\right)^2+\left(-\dfrac12\right)^2} =\dfrac{\sqrt5}2 \neq 1$

2. Given some vector $\vec x$ , you can get the unit vector in the same direction as

$\vec A = -12\,\vec\imath + 9\,\vec\jmath \\\\ \vec B = 15\,\vec\imath-20\,\vec\jmath$

then the unit vectors in the direction of $\vec A$ and $\vec B$ , respectively, are

$\dfrac{\vec A}{\|\vec A\|} = \dfrac{-12\,\vec\imath+9\,\vec\jmath}{\sqrt{(-12)^2+9^2}} = \dfrac{-12\,\vec\imath+9\,\vec\jmath}{15} = -\dfrac45\,\vec\imath + \dfrac35\,\vec\jmath \\\\ \dfrac{\vec B}{\|\vec B\|} = \dfrac{15\,\vec\imath-20\,\vec\jmath}{\sqrt{15^2+(-20)^2}} = \dfrac{15\,\vec\imath-20\,\vec\jmath}{25} = \dfrac35\,\vec\imath - \dfrac45\,\vec\jmath$

$\vec A = \|\vec A\| \left(\cos(180^\circ-\theta)\,\vec\imath + \sin(180^\circ-\theta)\,\vec\jmath\right) \\\\ \vec A = 25 \left(-\sin(37^\circ)\,\vec\imath + \cos(37^\circ)\,\vec\jmath\right) \\\\ \vec A = -15\,\vec\imath + 20\,\vec\jmath$

$\vec B = \|\vec B\| \left(\cos(180^\circ + \alpha)\,\vec\imath + \sin(180^\circ+\alpha)\,\vec\jmath\right) \\\\ \vec B = 75 \left(-\sin(53^\circ)\,\vec\imath-\cos(53^\circ)\,\vec\jmath\right) \\\\ \vec B = -60\,\vec\imath - 45\,\vec\jmath$