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kvasek [131]
3 years ago
14

I need help !!!!! Show the work plz!!!!

Physics
1 answer:
horrorfan [7]3 years ago
7 0

Answer:

26) 2 meters a second

27) 2 meters a second

28) 5 meters a second

29) 8 km

Explanation:

1/.5 =2

8/4=2

50/10=5

8km×1= 8

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A box with a mass of 18 kg is pushed across the floor. It has coefficient of friction of 0.39. Calculate the force of friction i
Taya2010 [7]

Answer:

68.8 N

Explanation:

From the question given above, the following data were obtained:

Mass (m) of box = 18 Kg

Coefficient of friction (μ) = 0.39

Force of friction (F) =?

Next, we shall determine the normal force of the box. This is illustrated below:

Mass (m) of object = 18 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Normal force (N) =?

N = mg

N = 18 × 9.8

N = 176.4 N

Finally, we shall determine the force of friction experienced by the object. This is illustrated below:

Coefficient of friction (μ) = 0.39

Normal force (N) = 176.4 N

Force of friction (F) =?

F = μN

F = 0.39 × 176.4

F = 68.796 ≈ 68.8 N

Thus, the box experience a frictional force of 68.8 N.

3 0
2 years ago
What is the net force on a truck if the force of friction is 31 N and the force of the engine is 79 N?
Evgen [1.6K]

Answer:

Fr = 48 [N] forward.

Explanation:

Suppose the movement is on the X axis, in this way we have the force of the engine that produces the movement to the right, while the force produced by the brake causes the vehicle to decrease its speed in this way the sign must be negative.

∑F = Fr

F_{engine}-F_{brake} =F_{r}\\F_{r}=79-31\\F_{r}=48[N]

The movement remains forward, since the force produced by the movement is greater than the braking force.

3 0
2 years ago
A car drives around a curve with radius 400 m at a speed of 32 m/s. The road is banked at 7.0 degree. The mass of the car is 150
Ronch [10]

Answer:

The magnitude of the centripetal force to make the turn is 3,840 N.

Explanation:

Given;

radius of the cured road, r = 400 m

speed of the car, v = 32 m/s

mass of the car, m = 1500 kg

The magnitude of the centripetal force to make the turn is given as;

F_c = \frac{mv^2}{r}

where;

Fc is the centripetal force

F_c = \frac{mv^2}{r} \\\\F_c = \frac{(1500)(32)^2}{400}\\\\F_c = 3,840 \ N

Therefore, the magnitude of the centripetal force to make the turn is 3,840 N.

3 0
3 years ago
The zone of earthquakes and volcanoes surrounding the pacific ocean is called
gulaghasi [49]

Answer:

The Ring of Fire

Explanation:

The ring of fire is also called the Circum-Pacific Belt, it is a path along the pacific ocean consisting of active volcanoes and frequent earthquakes.

It has a length of approximately 40,000 kilometers. It lies on the edge of tectonic plates where the in-earth vibrations and geothermal energies are prone to erupt out.

Ring of fire inhibits about 75% o the earth's volcanoes and 95% of earthquakes occur in this region.

3 0
3 years ago
Match the term with each description:
Alex_Xolod [135]

Answer:

An acid is a compound that increases hydrogen ions (H+) when it is dissolved in a solution.

all I got

4 0
3 years ago
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