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anyanavicka [17]
3 years ago
12

What is the acceleration due to gravity? А B 9.2 12.3 С 8.83 D 9.81

Physics
1 answer:
SCORPION-xisa [38]3 years ago
8 0
Correct answer:

D) 9.81

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A woman holds a book by placing it between her hands such that she presses at right angles to the front and back covers. The boo
In-s [12.5K]

Answer:

Explanation:

In order to solve this problem we need to make a free body diagram of the book and the forces that interact on it. In the picture below you can see the free body diagram with these forces.

The person holding the book is compressing it with his hands, thus exerting a couple of forces of equal magnitude and opposite direction with value F.

Now the key to solving this problem is to analyze the equilibrium condition (Newton's third law) on the x & y axes.

To find the weight of the book we simply multiply the mass of the book by gravity.

W = m*g

W = 1.3[kg] * 9.81[m/s^2]

W = 12.75 [N]

7 0
3 years ago
This 80 kg car is moving at 20m/sec at the top where the hills radius is 100m. What is the centrifugal force?
earnstyle [38]
100 seconds is the right thing
3 0
3 years ago
A set of data is collected for object in an inelastic collision, as recorded in the table.
TiliK225 [7]

Answer:

To identify the momentum of object 1, you must multiply mass (m) and velocity(v) to find momentum.

Object 1 has momentum of 8 kg. m/s before collision.

Object 1 has momentum of 0 kg. m/s before collision.

The combined mass after the collision had a total momentum of 8 kg. m/s.

Explanation:

Momentum of the object is given by,

Momentum = mass × velocity

For object 1:

Momentum = mass × velocity

Momentum = 2 × 4

Momentum = 8 kg. m/s

For object 2:

Momentum = mass × velocity

Momentum = 6 × 0

Momentum = 0 kg. m/s

For object 1 + object 2:

Momentum = mass × velocity

Momentum = 8 × 1

Momentum = 8 kg. m/s

To identify the momentum of object 1, you must multiply mass (m) and velocity(v) to find momentum.

Object 1 has momentum of 8 kg. m/s before collision.

Object 1 has momentum of 0 kg. m/s before collision.

The combined mass after the collision had a total momentum of 8 kg. m/s.


5 0
4 years ago
A pendulum built from a steel sphere with radius r cm 5 and density stl kg m S 3 7800 is attached to an aluminum bar with length
Ad libitum [116K]

Answer:

a)  I = 0.0198 kg m² ,  b)    I = 21.85 kg m²

Explanation:

For this exercise we will use the definition of moment of inertia

        I = ∫ r² dm

For body with high symmetry they are tabulated

sphere  I = 2/5 m r²

bar with respect to  center of mass I = 1/12 m L²

let's calculate the mass of each body

bar

        ρ = m / V

        m = ρ V

        m = ρ l w h

where we are given the density of the bar rho = 32840 kg / m³ and its dimensions 1 m, 0.8 cm and 4 cm

        m = 32820 1 0.008 0.04

        m = 10.5 kg

Sphere

       M = ρ V

       V = 4/3 pi r³

       M = rgo 4/3 π r³

give us the density 37800 kg / m³ and the radius of 5 cm

       M = 37800 4/3 π 0.05³

       M = 19.8 kg

a) asks us for the moment of inertia of the sphere with respect to its center of mass

        I = 2/5 M r²

        I = 2/5 19.8 0.05²

        I = 0.0198 kg m²

b) the moment of inertia with respect to the turning point, for this we will use the theorem of parallel axes

        I = I_cm + M d2

where d is the distance from the body to the point of interest

        I_cm = 0.0198 kg m²

the distance to the pivot point is

        l = length of the bar + radius of the sphere

        l = 1 + 0.05 = 1.005 m

        I = 0.0198 + 19.8 1.05²

        I = 21.85 kg m²

8 0
3 years ago
What is the momentum of a 48.2N bowling ball with a velocity of 7.13m/s?
Vesna [10]

Answer:

Momentum, p = 34.937 kg-m/s

Explanation:

It is given that,

Force acting on the bowling ball, F = 48.2 N

Velocity of bowling ball, v = 7.13 m/s

We have to find the momentum of the ball. Momentum is given by :

p = mv........(1)

Firstly, calculating the mass of bowling ball using second law of motion. The force acting on the ball is gravitational force and it is given by :

F = m g    (a = g)

m=\dfrac{F}{g}

m=\dfrac{48.2\ N}{9.8\ m/s^2}

m = 4.9 kg

Now putting the value of m in equation (1) as :

p=4.9\ kg\times 7.13\ m/s

p = 34.937 kg-m/s

Hence, this is the required solution.

8 0
3 years ago
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