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3 years ago

A skiy diver, with parachute unopened, falls 625 m in 15.0s.

Physics

1 answer:

olganol [36]3 years ago

3 0

Answer:

average velocity = 6.25m/sec

Explanation:

given data:

for unopened

height = 625 m

time = 15 sec

for opened

height = 356 m

time = 142 sec

Unopened:

$V1 = \frac{625\ m}{15\ sec} = 41.67m/sec$

Opened:

$V2 = \frac{356\ m}{142\ sec} = 2.51m/sec$

we know that

Total Average Velocity $= \frac{Total\ distance}{Total\ time}$

average velocity $= \frac{981\ m}{157\ sec}$

average velocity = 6.25m/sec

downward direction.

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A point charge q = +4.50 nC moves through a potential difference ΔV = Vf − Vi = +27.0 V. What is the change in the electric pote

olganol [36]

Change in electric potential energy: 121.5 nJ

Explanation:

For a charged particle moving in an electric field, the change in electric potential energy of the particle is given by

$\Delta U = q \Delta V$

where:

q is the charge of the particle

$\Delta V$ is the potential difference between the initial and final position of the particle

For the point charge in this problem, we have:

$q=+4.50 nC$ is the charge

$\Delta V=+27.0 V$ is the potential difference

Therefore, the change in electric potential energy is

$\Delta U=(+4.50)(+27.0)=121.5 nJ$

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3 years ago

A uniform rod of length 50cm and mass 0.2kg is placed on a fulcrum at a distance of 40cm from the left end of the rod. At what d

oksano4ka [1.4K]

Answer:

x = 45 cm

Explanation:

Given that,

The length of a rod, L = 50 cm

Mass, m₁ = 0.2 kg

It is at 40cm from the left end of the rod.

We need to find the distance from the left end of the rod should a 0.6kg mass be hung to balance the rod.

The centre of mass of the rod is at 25 cm.

Taking moments of both masses such that,

$15\times 0.2=x\times 0.6\\\\x=\drac{3}{0.6}\\\\x=5\ cm$

The distance from the left end is 40+5 = 45 cm.

Hence, at a distance of 45 cm from the left end it will balance the rod.

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3 years ago

An electron is travelling in a straight line with a kinetic energy K = 1.60 x 10^-17J. What are (a) the magnitude and (b) the di

faust18 [17]

Answer:

(a) 1000 N/C

Explanation:

Kinetic energy of electron, K = 1.6 x 10^-17 J

distance, d = 10 cm = 0.1 m

Let the potential difference is V and the electric field is E.

(a) The relation between the kinetic energy and the potential difference is

K = e V

V = K / e

Where, e be the electronic charge = 1.6 x 10^-19 C

V = $\frac{1.6\times 10^{-17}}{1.6\times 10^{-19}}$

V = 100 V

The relation between the electric field and the potential difference is given by

V = E x d

100 = E x 0.1

E = 1000 N/C

(b) The force acting on the electron, F = q E

where q be the charge on electron

So, F = -e x E

It means the direction of electric field and the force are both opposite to each other.

The direction of electric field and the force on electron is shown in the diagram.

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4 years ago

Which physical property is used to identify matter based on solubility

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Volume is the answer.

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3 years ago

A factory emits pollutants at a rate of 25 g/s. The factory is located between two mountain ranges resulting in an effective val

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Answer:

$1.25\ \mu\text{g/m}^3$

Explanation:

v = Velocity of the breeze = 4 m/s

w = Width of the valley = 5000 m

h = Height of the valley = 1000 m

Volumetric flow rate is given by

$\dot{V}=vwh\\\Rightarrow \dot{V}=4\times 5000\times 1000\\\Rightarrow \dot{V}=2\times10^{7}\ \text{m}^3/\text{s}$

$\dot{m}$ = Mass flow rate of pollutant = 25 g/s = $25\times 10^6\ \mu\text{g/s}$

Concentration is given by

$C=\dfrac{\dot{m}}{\dot{V}}\\\Rightarrow C=\dfrac{25\times 10^6}{2\times 10^7}\\\Rightarrow C=1.25\ \mu\text{g/m}^3$

The steady state concentration of pollutants in the valley, is $1.25\ \mu\text{g/m}^3$ .

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3 years ago