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lapo4ka [179]
3 years ago
13

A skiy diver, with parachute unopened, falls 625 m in 15.0s.

Physics
1 answer:
olganol [36]3 years ago
3 0

Answer:

average velocity = 6.25m/sec

Explanation:

given data:

for unopened

height = 625 m

time  = 15 sec

for opened

height = 356 m

time =  142 sec

Unopened:

V1 = \frac{625\ m}{15\ sec} = 41.67m/sec

Opened:

V2 = \frac{356\ m}{142\ sec} = 2.51m/sec

we know that

Total Average Velocity= \frac{Total\ distance}{Total\ time}

average velocity= \frac{981\ m}{157\ sec}

average velocity = 6.25m/sec

downward direction.

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F_{g} - F_{d} = 48N

48N = (6.00kg)(9.81m/s^2) - F_{d} 

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A rock is dropped from a distance RE above the surface of the earth, and is observed to have kinetic energy K1 when it hits the
goblinko [34]

Answer:

\dfrac{K_2}{K_1}=\dfrac{4}{3}

Explanation:

When an object strikes the ground, the potential energy of the rock gets converted to the kinetic energy.

A rock is dropped from a distance R_e above the surface of the earth and is observed to have kinetic energy K_1 when it hits the ground.

For another rock, It is dropped from twice the height 2R_e above the earth’s surface and has kinetic energy K_2 when it hits.              

For the first rock, K_1=GMm(\dfrac{1}{R_e}-\dfrac{1}{2R_e})=\dfrac{GMm}{2R_e}..............(1)

For the second rock, K_2=GMm(\dfrac{1}{R_e}-\dfrac{1}{3R_e})=\dfrac{2GMm}{3R_e}..............(2)

Dividing equation (2) by (1) we get :

\dfrac{K_2}{K_1}=\dfrac{4}{3}

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