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3 years ago

What organ(s) does Sodium Hydroxide target if you come into contact with it?

1 answer:

5 0

Hey mate!
You stuck?

Sodium Hydroxide is a corrosive formula. It causes severe skin and eye burns and digestive tract burns. Dust or vapor from the formula is extremely irritating to the eyes and respiratory tract. The material reacts to water. Target organs of Sodium Hydroxide consists of Eyes, skin, lungs and the respiratory system.

Hope this helps! :)

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The accepted value for the molar volume of a gas is 22.4 L. Sarah’s experimental data indicated that a mole of a gas had a volum

Law Incorporation [45]

Answer:

12.5%.

Explanation:

The following data were obtained from the question:

Accepted value = 22.4 L

Experimental value = 19.6L

Percentage error =.?

Percentage error can be obtained by using the following formula:

Percentage error = |Experimental value – Actual value | / actual value × 100

Percentage error = |19.6 – 22.4|/22.4 × 100

Percentage error = 2.8 /22.4 × 100

Percentage error = 280/22.4

Percentage error = 12.5%

Therefore, the percentage error of Sarah is 12.5%

4 0

4 years ago

What is the answer? Please

balandron [24]

I can’t see the whole question?

8 0

3 years ago

What is the volume of gas at a temperature of 200.0 K if its original volume was

Bumek [7]

Answer:

200.0 K

Explanation:

temperature 400.9 K

7 0

3 years ago

Which of the following is an example of sound waves being reflected?

pshichka [43]

Answer: C

This is an example of sound wave reflection, also known as "echoing".

7 0

4 years ago

Mercury(II) oxide (HgO) decomposes to form mercury (Hg) and oxygen (O2). The balanced chemical equation is shown below. 2HgO Rig

BigorU [14]

Taking into account the reaction stoichiometry, the correct answer is the third option: 15.63 moles of HgO are needed to produce 250 g of O₂.

In first place, the balanced reaction is:

2 HgO → 2 Hg + O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

HgO: 2 moles
Hg: 2 moles
O₂: 1 moles

The molar mass of the compounds is:

HgO: 216.59 g/mole
Hg: 200.59 g/mole
O₂: 32 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

HgO: 2 moles× 216.59 g/mole= 433.18 grams
Hg: 2 moles× 200.59 g/mole= 401.18 grams
O₂: 1 mole× 32 g/mole= 32 grams

Then the following rule of three can be applied: if by reaction stoichiometry 32 grams of O₂ are produced by 2 moles of HgO, 250 grams of O₂ are produced from how many moles of HgO?

$moles of HgO=\frac{250 grams of O_{2} x2 moles of HgO}{32grams of O_{2}}$

<u><em>moles of HgO= 15.625 moles≅ 15.63 moles</em></u>

Finally, the correct answer is the third option: 15.63 moles of HgO are needed to produce 250 g of O₂.

Learn more about reaction stoichiometry:

5 0

3 years ago