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Norma-Jean [14]
4 years ago
10

Calculate the flow rate of blood (of density 0.846 g/cm3 ) in an aorta with a crosssectional area of 1.36 cm2 if the flow speed

is 48.5 cm/s. Answer in units of g/s.
Physics
1 answer:
Roman55 [17]4 years ago
6 0

Answer:

55.80 g/s

Explanation:

From the question,

Flow rate = density×Area×velocity.

φ = ρ×A×V................... Equation 1

Where φ = flow rate of blood, ρ = density of blood, A = cross sectional area of blood, V = velocity of blood.

Given: ρ = 0.846 g/cm³, A = 1.36 cm², V = 48.5 cm/s.

Substitute these values into equation 1

φ = 0.846×1.36×48.5

φ = 55.80 g/s

Hence, the flow rate of  the blood = 55.80 g/s

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what is the minimum (nonzero) thickness of the coating for which there is maximum transmission of the light into the rod?
timofeeve [1]

The thickness is 155 nm at t1.

The thickness is 77.3 nm at t2.

The inquiry informs us that the laser light's wavelength is λ=510nm

The plastic rod's refractive index is n=1.30

The transparent coating's refractive index is nr=1.65

Minimum reflection would be required for maximal light transmission into the rod, and it is mathematically described as

2t1=510+10⁻⁹/1.65

t1=510+10⁻⁹/1.65*2

t1=155nm

where m is the interference order, which equals 1.

2t2= {m+1/2} λ/nr

The thickness is t replacing values

t1=155 nm

The highest reflection would occur for minimal light penetration through the rod, and this maximum reflection is mathematically described as

2t2= [m+1/2] λ/nr

t2=77.3 nm

The complete question is- Laser light of wavelength 510 nm is traveling in air and shines at normal incidence onto the flat end of a transparent plastic rod that has n = 1.30. The end of the rod has a thin coating of a transparent material that has refractive index 1.65. What is the minimum (nonzero) thickness of the coating (a) for which there is maximum transmission of the light into the rod; (b) for which transmission into the rod is minimized?

Learn more about reflection here-

brainly.com/question/15487308

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2 years ago
How long does it take a car traveling at 45km/h to travel 100 m
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Explanation:

45 \frac{km}{hr}  \times  \frac{1000m}{1km}  = 45000 \frac{m}{hr}  \\  \frac{100m}{45000 \frac{m}{hr} }  =  \frac{1}{450} hr \\  \frac{1}{450} hr \times  \frac{60mins}{1hr}  =  \frac{2}{15} mins = 0.133mins

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It would be a raindrop depending on if the ship is moving or not. If the ship is not moving, then the raindrop would have more momentum. But, if the ship were moving, then it would have more momentum. Because momentum equals mass times velocity.

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Answer:
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