Answer:
<em>D. Hydrochloric acid solution with a pH of 1</em>
Explanation:
<span> Vertical height of longest escalator in free world = 58.8 sin 32.4 = 31. 5 m
Karen's mass = 54.6 kg
Work done on Karen = mgh = 54.6(9.81)(31.5) = 1.69e4 J = 16.9 KJ ANS </span>
Answer:
The answer to your question is P = 0.18 atm
Explanation:
Data
mass of O₂ = 0.29 g
Volume = 2.3 l
Pressure = ?
Temperature = 9°C
constant of ideal gases = 0.082 atm l/mol°K
Process
1.- Convert the mass of O₂ to moles
16 g of O₂ -------------------- 1 mol
0.29 g of O₂ ---------------- x
x = (0.29 x 1)/16
x = 0.29/16
x = 0.018 moles
2.- Convert the temperature to °K
Temperature = 9 + 273 = 282°K
3.- Use the ideal gas law ro find the answer
PV = nRT
-Solve for P
P = nRT/V
-Substitution
P = (0.018 x 0.082 x 282) / 2.3
-Simplification
P = 0.416/2.3
-Result
P = 0.18 atm
Physical Properties
Sucrose has a monoclinic crystal structure.
When subjected to high temperatures (over 186oC), this compound decomposes, yielding caramel.
Its solubility in water at a temperature of 20oC is 203.9g/100mL.
The standard enthalpy of combustion corresponding to sucrose is 5647 kJ. mol-1.
<span>4.3065 g
First, lookup the atomic weights of all the elements involved.
Atomic weight of Calcium = 40.078
Atomic weight of Carbon = 12.0107
Atomic weight of Hydrogen = 1.00794
Atomic weight of Oxygen = 15.999
Atomic weight of Sulfur = 32.065
Now calculate the molar masses of the reactants and product
Molar mass H2SO4 = 2 * 1.00794 + 32.065 + 4 * 15.999
= 98.07688 g/mol
Molar mass CaCO3 = 40.078 + 12.0107 + 3 * 15.999
= 100.0857 g/mol
Molar mass CaSO4 = 40.078 + 32.065 + 4 * 15.999
= 136.139 g/mol
The balanced reaction for H2SO4 with CaCO3 is
CaCO3 + H2SO4 ==> CaSO4 + H2O + CO2
So it takes 1 mole each of CaCO3 and H2SO4 to produce 1 mole of CaSO4. Let's see how many moles of CaCO3 and H2SO4 we have.
CaCO3: 3.1660 g / 100.0857 g/mol = 0.031632891 mol
H2SO4: 3.2900g / 98.07688 g/mol = 0.033545113 mol
We have a slight excess of H2SO4, so the amount of CaCO3 is the limiting reactant and we should have 0.031632891 moles of product. To determine its mass, multiply the number of moles by the molar mass computed earlier.
0.031632891 mol * 136.139 g/mol = 4.306470148 g
Since we have 5 significant figures in our data, round the result to 5 figures, giving 4.3065 g</span>