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Salsk061 [2.6K]
4 years ago
7

the coefficient of friction between a hard rubber and normal street pavement is 0.8 What is the steepest incline on which a car

can be safely parked​
Physics
1 answer:
ryzh [129]4 years ago
6 0

Answer:

38.7°

Explanation:

Draw a free body diagram of the car.  There are three forces:

Weight force mg pulling down,

Normal force N pushing up perpendicular to the incline,

and friction force Nμ pushing parallel up the incline.

Sum of forces in the perpendicular direction:

∑F = ma

N − mg cos θ = 0

N = mg cos θ

Sum of forces in the parallel direction:

∑F = ma

Nμ − mg sin θ = 0

Nμ = mg sin θ

μ = (mg sin θ) / N

μ = (mg sin θ) / (mg cos θ)

μ = tan θ

Given μ = 0.8:

θ = tan⁻¹(0.8)

θ = 38.7°

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3 years ago
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7nadin3 [17]

Answer:

12.245m3

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4 years ago
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Hope this helps

3 0
3 years ago
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