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olga nikolaevna [1]
3 years ago
14

Help please due tomorrow

Physics
1 answer:
Anni [7]3 years ago
6 0
Hope this helps!!!!

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A .005kg projectile leaves a 1500kg launcher with a velocity of 750 m/s. What is the recoil velocity of the projectile
docker41 [41]

Answer:

The recoil velocity of the projectile is 0.0025m/s

Explanation:

Given:

Mass of the projectile =0.005kg

Mass of the launcher = 1500kg

Velocity =  750 m/s.

To Find:

The recoil velocity of the projectile = ?

Solution:

The recoil velocity is the obtained by dividing the "recoil momentum"  by the "mass of the recoil body".  The recoil momentum is equal to the momentum of the other body. The momentum of the other body is equal to it mass times its velocity.

Lets find the recoil momentum,

Recoil momentum = mass of the projectile X velocity

Recoil momentum =0.005 \times 750

Recoil momentum = 3.75

Now Recoil Velocity,

Recoil Velocity = \frac{\text { Recoil Momentum}}{\text {Mass of the launcher}}

Recoil Velocity = \frac{ 3.75}{1500}

Recoil Velocity = 0.0025m/s

7 0
4 years ago
How do atoms join together?
miv72 [106K]

Answer:

Atoms can be joined together by chemical bonds.

Explanation:

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8 0
3 years ago
Read 2 more answers
PRACTIC
klasskru [66]

Answer:

2482 Kg.m/s

Explanation:

Momentum is a product of mass of an object and its velocity with consideration to the direction of velocity and expressed as, p=mv where m represent mass of the ostrich and v is the velocity in m/s, p is momentum.

Substituting the mass of ostrich with 146 kg and the velocity as 17 m/s then the momentum of the ostrich is equal to

P=146*17=2482 kg.m/s

Therefore, the momentum of ostrich is equal to 2482 kg.m/s

6 0
4 years ago
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