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fredd [130]
3 years ago
7

Consider four elements from Group 17: fluorine in the second period, chlorine in the third period, bromine in the fourth period,

and iodine in the fifth period. Which element has the largest first ionization energy? A. fluorine B. chlorine C. bromine D. iodine E. You need more data to predict the first ionization energy of these elements.
Chemistry
1 answer:
nika2105 [10]3 years ago
6 0

Answer:

A. Fluorine

Explanation:

I got it right on Plato.

You might be interested in
While finding the number of molecules of oxygen molecules present in 3.65 moles of Na2SO4 the conversion factor used would be
zvonat [6]

Answer

Avogadro's number: One mole of any substance contains 6.022×10²³ molecules

Explanation

While finding the number of moles of oxygen molecules present in 3.65 moles of Na2SO4 the conversion factor used would be Avodagro's number, which is

One mole of any substance contains 6.022×10²³ molecules.

8 0
1 year ago
Write the balanced equation for the equilibrium reaction for the dissociation ofsilver chloride in water, and write the K expres
Marizza181 [45]

Answer:

See explanation

Explanation:

Hello there!

In this case, since the the concentrations are not given, and not even the Ksp, we can solve this problem by setting up the chemical equation, the equilibrium constant expression and the ICE table only:

AgCl(s)\rightleftharpoons Ag^+(aq)+Cl^-(aq)

Next, the equilibrium expression according to the produced aqueous species as the solid silver chloride is not involved in there:

Ksp=[Ag^+][Cl^-]

And therefore, the ICE table, in which x stands for the molar solubility of the silver chloride:

       \ \ \ \ \ \ \ \ \ \ \ \ \ \ AgCl(s)\rightleftharpoons Ag^+(aq)+Cl^-(aq)

I          -                   0             0

C        -                   +x           +x

E        -                    x             x

Which leads to the following modified equilibrium expression:

Ksp=x^2

Unfortunately, values were not given, and they cannot be arbitrarily assigned or assumed.

Regards!

6 0
3 years ago
Which element does this Bohr model represent? (look at a periodic table if needed)
Serjik [45]
Circulating round the nucleus are the electrons in various orbits of different energy levels. Electrons are negatively charged and represented by the symbol 'e'. In the given image the number of protons are -6. Hence the element in question is Carbon as Carbon has the atomic number 6.
6 0
3 years ago
Due is 10 min please help
Nonamiya [84]

Answer:

its c hope this helped;)

Explanation:

5 0
3 years ago
Help help help.
Whitepunk [10]
I think B
Hope this helps!
4 0
3 years ago
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