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Nesterboy [21]
3 years ago
5

2. A 0.8 kg tetherball hangs on the end of a cord. It is hit by a child and rises 2.1 m above the ground. a. What is the maximum

gravitational potential energy of the ball?
Physics
1 answer:
skad [1K]3 years ago
3 0

Answer:

E = 16.464 J

Explanation:

Given that,

Mass of tetherball, m = 0.8 kg

It is hit by a child and rises 2.1 m above the ground, h = 21. m

We need to find the maximum gravitational potential energy of the ball. The formula for the gravitational potential energy is given by :

E = mgh

g is acceleration due to gravity

E = 0.8 kg × 9.8 m/s² × 2.1 m

= 16.464 J

So, the maximum potential energy of the ball is 16.464 J.

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A dime is placed in front of a concave mirror that has a radius of curvature R = 0.40 m. The image of the dime is inverted and t
andrew11 [14]

Answer:

distance between the dime and the mirror, u = 0.30 m

Given:

Radius of curvature, r = 0.40 m

magnification, m = - 2 (since,inverted image)

Solution:

Focal length is half the radius of curvature, f = \frac{r}{2}

f = \frac{0.40}{2} = 0.20 m

Now,

m = - \frac{v}{u}

- 2 = -\frac{v}{u}

\frac{v}{u} = 2                  (2)

Now, by lens maker formula:

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}

\frac{1}{v} = \frac{1}{f} - \frac{1}{u}

v = \frac{uf}{u - f}            (3)

From eqn (2):

v = 2u

put v = 2u in eqn (3):

2u = \frac{uf}{u - f}

2 = \frac{f}{u - f}

2(u - 0.20) = 0.20

u = 0.30 m

6 0
3 years ago
The cost, density and resistivity of copper, steel and aluminum
otez555 [7]
Density of copper: 8,9
Density of steel: 7,7
Density of aluminum: 2,7
And
Resistivity of copper: 1,7
Resistivity of steel: 16,9
Resistivity of aluminum: <span>2,7</span>

Hope I Helped You!!! :-)

Have A Good Day!!!
3 0
3 years ago
I need help... anyone know this?
julsineya [31]

Answer:mp

Explanation:

7 0
3 years ago
Light waves do not need a medium to travel through. true or false.
melamori03 [73]

Light travels in electromagnetic waves in the form of photons. What do photons travel in? Can a frequency have weight? Carry weight? According to Einstien a photon with energy proportional to its frequency basically explains ultraviolet light(among other things), so does that mean light travels within a "larger" version of itself?

We know that light doesn't need a medium through which to travel because the speed of light is experimentally constant: independent of the movement of the source or detector or the direction in which it travels.

Light contrasts with sound, which travels through the air (or some other material medium). If you're stationary with respect to the air, then the speed of sound is the same in all directions. But if you're moving with respect to the air, the speed of sound will be the same in all directions relative to the air---which means that sound coming up in front of you will seem faster and sound catching up to you from behind will seem slower.

If light were a disturbance in a medium, it would exhibit the same behaviour. But light never does---its speed is the same under all circumstances. So it does you no good to postulate an aether. You can still do it, but it makes the theory more complicated than necessary. The only reason to postulate an aether is that you're uncomfortable with the idea of waves not needing a medium. But our modern understanding of quantum mechanics is that all kinds of particles have a wavelike nature, so, if you accept that matter can travel through empty space, you should have no problem accepting the same for light.

so it's true

6 0
3 years ago
Read 2 more answers
A coin is resting on the bottom of an empty container. The container is then filled to the brim three times, each time with a di
Virty [35]

Answer:

Refractive index of liquid C > Refractive index of liquid B > Refractive index of liquid A

Explanation:

Let the depth of each section is h.

That means the real depth for each section is h.

Apparent depth is liquid A is 7 cm.

Apparent depth in liquid B is 6 cm.

Apparent depth in liquid C is 5 cm.

by the formula of the refractive index

n = real depth / apparent depth

where, n is the refractive index of the liquid.

For liquid A:

n_{A}=\frac{h}{7}    .... (1)

For liquid B:

n_{B}=\frac{h}{6}   ..... (2)

For liquid C:

n_{C}=\frac{h}{5}     ..... (3)

By comparing all the three equations

nc > nB > nA

Refractive index of liquid C > Refractive index of liquid B > Refractive index of liquid A

5 0
3 years ago
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