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Nesterboy [21]
3 years ago
5

2. A 0.8 kg tetherball hangs on the end of a cord. It is hit by a child and rises 2.1 m above the ground. a. What is the maximum

gravitational potential energy of the ball?
Physics
1 answer:
skad [1K]3 years ago
3 0

Answer:

E = 16.464 J

Explanation:

Given that,

Mass of tetherball, m = 0.8 kg

It is hit by a child and rises 2.1 m above the ground, h = 21. m

We need to find the maximum gravitational potential energy of the ball. The formula for the gravitational potential energy is given by :

E = mgh

g is acceleration due to gravity

E = 0.8 kg × 9.8 m/s² × 2.1 m

= 16.464 J

So, the maximum potential energy of the ball is 16.464 J.

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What is the molality of a solution that contains 54 grams of NaOH dissolved in 1.50 kg of water? (The molar mass of NaOH 40.00 g
expeople1 [14]

Answer:

0.900 mol/kg

Explanation:

Molality is moles of solute per kilograms of solvent.

Converting 54 grams of NaOH to moles:

54 g NaOH × (1 mol NaOH / 40.00 g NaOH) = 1.35 mol NaOH

So the molality is:

m = (1.35 mol) / (1.50 kg)

m = 0.900 mol/kg

8 0
4 years ago
An automobile tire having a temperature of −1.6 ◦C (a cold tire on a cold day) is filled to a gauge pressure of 22 lb/in2 . What
r-ruslan [8.4K]

Answer:

25.8 lb/in²

Explanation:

Gay-Lussac's law tells us that given an ideal gas of a certain mass has a constant volume, the pressure exerted on the sides of its container is directly proportional to its absolute temperature.

\frac{P_{1} }{T_{1} } = \frac{P_{2} }{T_{2} } \\\\\frac{22}{-1.6+273.15} =\frac{P_{2} }{45+273.15} \\\\P_{2} = \frac{22*318.15}{271.55} = 25.8lb/in^{2}

4 0
3 years ago
PLZ HURRY!!!
MAVERICK [17]

Answer:

7.8 miles just did it

Explanation:

4 0
3 years ago
The collision of the molecules of a fluid inside the surface of their container best describes which of the following?
LUCKY_DIMON [66]
Pressure is the answer
5 0
4 years ago
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At time t=0 a proton is a distance of 0.360 m from a very large insulating sheet of charge and is moving parallel to the sheet w
Yuki888 [10]

Explanation:

Formula for the electric field due to the infinite sheet of charge is as follows.

               E = \frac{\sigma}{2 \epsilon_{o}}

where,   \sigma = surface charge density

Now, formula for electric force acting on the proton is as follows.

             F = eE

where,    e = charge of the proton

According to the Newton's second law of motion, the net force acting on the proton is as follows.

                       F = ma

                 a = \frac{eE}{m}

                    = \frac{e(\frac{\sigma}{2 \epsilon_{o}})}{m}

                    = \frac{e \sigma}{2m \epsilon_{o}}

According to the kinematic equation, speed of the proton in perpendicular direction is as follows.

              v_{f} = v_{i} + at

                     = (0 m/s) + \frac{e \sigma}{2 m \epsilon_{o}}t

                     = \frac{1.6 \times 10^{-19}C \times 2.34 \times 10^{-9} C/m^{2} \times 5.40 \times 10^{-8}s}{2 \times (1.67 \times 10^{-27} kg)(8.85 \times 10^{-12} C^{2}/Nm^{2}}

                     = 683.974 m/s

Hence, total speed of the proton is as follows.

                v' = \sqrt{(960 m/s)^{2} + (683.974 m/s)^{2}}

                    = \sqrt{921600 + 467820.43}

                    = \sqrt{1389420.43}

                    = 1178.73 m/s

Therefore, we can conclude that speed of the proton is 1178.73 m/s.

3 0
3 years ago
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