To solve this problem, we apply the concepts related to the sum of forces and balance in a diagram that will be attached, in order to identify the behavior, direction and sense of the forces. The objective is to find an expression that is in terms of the mass, the angle, the coefficient of friction and the length that allows us to identify when the ladder begins to slip. For equilibrium of the ladder we have,



Now we have that


And for equilibrium of the two forces we have finally

Rearranging to find the distance,


So if we have that the frictional force is equivalent to




With this value we have that


Therefore can go around to 5.19m before the ladder begins to slip.
<u>Answer:</u>
Cheryl, Heather and Keaton all are correct.
<u>Explanation:</u>
Everything around you is made of matter and matter is anything that has mass and occupies space or in other words, anything which has volume is called matter.
Here, in the given example, Cheryl, Heather and Keaton all are correct because the mug, the hot chocolate which is inside the mug and the steam coming out of it, all have mass. Therefore, all are correct except for Mikayla.
Answer:
The focal length of the lens is 34.047 cm
The power of the needed corrective lens is 2.937 diopter.
Explanation:
Distance of the object from the lens,u = 26 cm
Distance of the image from the lens ,v= -110 cm
(Image is forming on the other side of the lens)
Since ,lens of the human eye is converging lens,convex lens.
Using a lens formula:


f = 34.047 cm = 0.3404 m
Power of the lens = P

The kinetic energy of an object increases as its decreases <span>its potential energy as the sum of energy will remain constant.
In short, Your Answer would be "Decreases"
Hope this helps!</span>