Answer:
AB = =
Step-by-step explanation:
A (-3,4); B (6,1)
Let H lays on x-axis and AH ⊥ Ox --> H (xA,0) = (-3,0)
Let K lays on AH and BK ⊥ AH --> K (xA, yB) = (-3, 1)
AK = |yA - yK| = |4 - 1| = 3
BK = |xB - xK| = |6 - -3| = 9
ABK is a right triangle (AKB = 90)
--> AB^2 = AK^2 + BK^2 = 3^2 + 9^2 = 90
--> AB = =
Or, you can use the formula:
AB = and get the same result.
This formula can be used to find the distance between any 2 points.