1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
natima [27]
3 years ago
8

You doubled the voltage frequency in an RL series AC circuit, the inductive resistance would?

Engineering
2 answers:
Vesna [10]3 years ago
7 0

<u>Answer: </u>

When the voltage frequency is doubled, the resistance will remain same in RL series AC circuit.

<u>Explanation: </u>

A circuit that has an inductance L and Resistance R is said to be a RL or LR circuit. The inductance in the circuit is directly proportional to the Frequency F and Inductive Reactance XL of the circuit.  

\mathrm{XL}=2 \times \pi \times \mathrm{F} \times \mathrm{L}

So, whenever there is a change in the frequency it directly changes the inductance and inductive reactance of the circuit but Resistance will remain unaffected.

Resistance in a RL circuit is independent of the frequency. Therefore, in the given case, the resistance will remain the same only the reactance will get doubled.

Ivenika [448]3 years ago
6 0

Answer:

Remain the same.

Explanation:

If you doubled the voltage frequency in an RL series AC circuit, the inductive resistance would <u>remain the same</u>.

You might be interested in
Line.
Veronika [31]

Air supplied to a pneumatic system is supplied through the C. Actuator

Explanation

Pneumatic systems are like hydraulic systems, it is just that these systems uses compressed air rather than hydraulic fluid.  Pneumatic systems are used widely across the industries. these pneumatic systems needs a constant supply of compressed air to operate. This is provided by an air compressor. The compressor sucks in air at a very high rate from the environment and stores it in a pressurized tank. the Air is supplied thereafter with the help of a actuator valve that is a more sophisticated form of a valve.

From the above statement it is clear that Air supplied to a pneumatic system is supplied through the  Actuator

7 0
3 years ago
Which of the following conditions were present in over 80% of paddling fatalities from 1995-2000?
Minchanka [31]

Answer:

80% of the people that were killed weren't wearing a safety flotation device ( in correct terminology Personal Flotation Device, or PFD )

Explanation:

Hence they drowned due to the lack of safety.

3 0
3 years ago
You find an unnamed fluid in the lab we will call Fluid A. Fluid A has a specific gravity of 1.65 and a dynamic viscosity of 210
Naily [24]

Answer:

1.2727 stokes

Explanation:

specific gravity of fluid A = 1.65

Dynamic viscosity = 210 centipoise

<u>Calculate the kinematic viscosity of Fluid A </u>

First step : determine the density of fluid A

Pa = Pw * Specific gravity =  1000 * 1.65 = 1650 kg/m^3

next : convert dynamic viscosity to kg/m-s

210 centipoise = 0.21 kg/m-s

Kinetic viscosity of Fluid A = dynamic viscosity / density of fluid A

                                            = 0.21 / 1650 = 1.2727 * 10^-4 m^2/sec

Convert to stokes = 1.2727 stokes

4 0
3 years ago
Who works alongside and assists the engineers?
nika2105 [10]

Answer:

<u>Assistants</u><u> </u><u>works alongside and assists the engineers.</u>

5 0
3 years ago
At a certain location, wind is blowing steadily at 5 mph. Suppose that the mass density of air is 0.0796 lbm/ft3 and determine t
nlexa [21]

Answer:

The radius of a wind turbine is 691.1 ft

The power generation potential (PGP) scales with speed at the rate of 7.73 kW.s/m

Explanation:

Given;

power generation potential (PGP) = 1000 kW

Wind speed = 5 mph = 2.2352 m/s

Density of air = 0.0796 lbm/ft³ = 1.275 kg/m³

Radius of the wind turbine r = ?

Wind energy per unit mass of air, e = E/m = 0.5 v² = (0.5)(2.2352)²

Wind energy per unit mass of air = 2.517 J/kg

PGP = mass flow rate * energy per unit mass

PGP = ρ*A*V*e

PGP = \rho *\frac{\pi r^2}{2} *V*e  \\\\r^2 = \frac{2*PGP}{\rho*\pi *V*e} , r=\sqrt{ \frac{2*PGP}{\rho*\pi *V*e}} = \sqrt{ \frac{2*10^6}{1.275*\pi *2.235*2.517}}

r = 210.64 m = 691.1 ft

Thus, the radius of a wind turbine is 691.1 ft

PGP = CVᵃ

For best design of wind turbine Betz limit (c) is taken between (0.35 - 0.45)

Let C = 0.4

PGP = Cvᵃ

take log of both sides

ln(PGP) = a*ln(CV)

a = ln(PGP)/ln(CV)

a = ln(1000)/ln(0.4 *2.2352) = 7.73

The power generation potential (PGP) scales with speed at the rate of 7.73 kW.s/m

5 0
3 years ago
Other questions:
  • A turbine produces shaft power from a gas that enters the turbine with a (static) temperature of 628 K, a velocity of 143 m/s an
    7·1 answer
  • - Viscoelastic stress relaxation
    7·1 answer
  • Which one of the following is a list of devices from least efficient to most efficient
    9·1 answer
  • i need jacket for my daughter who will be going on a girls scouts camping trip it cannot be bulky because she is limited to one
    8·2 answers
  • Using the technique of bitwise ANDing, find the IP address of the network # (this could be a network or subnet) on which the mac
    14·1 answer
  • Sun of first 1 nayural numbers​
    7·2 answers
  • The section should span between 10.9 and 13.4 cm (4.30 and 5.30 inches) as measured from the end supports and should be able to
    5·1 answer
  • At a retirement party, a coworker described terry as dedicated
    9·1 answer
  • Who here likes to play project gotham racing?<br> will mark brainlyest
    8·2 answers
  • What is photosynthesis​
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!