You doubled the voltage frequency in an RL series AC circuit, the inductive resistance would?
2 answers:
<u>Answer: </u>
When the voltage frequency is doubled, the resistance will remain same in RL series AC circuit.
<u>Explanation: </u>
A circuit that has an inductance L and Resistance R is said to be a RL or LR circuit. The inductance in the circuit is directly proportional to the Frequency F and Inductive Reactance XL of the circuit.
So, whenever there is a change in the frequency it directly changes the inductance and inductive reactance of the circuit but Resistance will remain unaffected.
Resistance in a RL circuit is independent of the frequency. Therefore, in the given case, the resistance will remain the same only the reactance will get doubled.
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Answer:
Below see details
Explanation:
A) It is attached. Please see the picture
B) First to calculate the overall mean,
μ=65∗25/75+80∗25/75+95∗25/75
μ=65∗25/75+80∗25/75+95∗25/75 = 80
Next to calculate E(MSTR) = σ2+(1/r−1) ∑ni(μi−μ)^2 = 5634
And E(MSE) = σ^2= 9
C) Yes, it is substantially large than E(MSE) in this case.
D) If we sampled 25 employees from each group, we are likely to get a F statistics to indicate differences of job satisfactions among three types of length of service of employees.
Answer:
a)Wt =25.68 lbf
b)Wt = 150 lbf
F= 899.59 N
Explanation:
Given that
m= 150 lbm
a)
Weight on the spring scale(Wt) = m g
We know that
Wt = 150 x 5.48/32 lbf
Wt =25.68 lbf
b)
On the beam scale
This is scale which does not affects by gravitational acceleration.So the wight on the beam scale will be 150 lbf.
Wt = 150 lbf
If the plane is moving upward with acceleration 6 g's then the for F
F = m a
We know that
a=6 g's
So
F = 90 x 9.99 N
F= 899.59 N