Can a particle moving with instantaneous speed 3.00 m/s on a path with radius of curvature 2.00 m have an acceleration of magnit
1 answer:
Circular acceleration has 2 components, the centripetal and tangential acceleration.
The formula for calculating the centripetal acceleration of a particle is:
= v^2/r
Where v is the velocity or instantaneous speed and r is the radius.
= (3^2)/6 = 1.5 m/s^2
Assuming that the particle stays on the same circular path, another thing it can have is the tangential acceleration. While the centripetal acceleration is constant, tangential acceleration depends on the location of the particle in the circular path. So to answer A and B, yes we can have an acceleration of 6 and 4 respectively.
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Answer:
1.0 dioptres
Explanation:
Farsightedness is an eye defect in which a person can see far objects clearly but not near objects. That implies that the patients' near point is farther than 25cm which is the normal least distance of distinct vision.
Farsightedness results from the eyeball being too long or the crystalline lens not being sufficiently converging.
Carol is farsighted with a near point of about a meter (100cm). We desire to make a lens to enable her near point be reduced to about 50cm. The focal length and power of this lens is calculated in the image attached.
The power of a lens is the inverse of its focal length in meters hence the 100 in the formula for power of the lens.
