Answer:
CH₃O
Explanation:
Data Given:
Molecular Formula = C₂H₆O₂
Empirical Formula = ?
Solution
Empirical Formula:
Empirical formula is the simplest ration of atoms in the molecule but not all numbers of atoms in a compound.
So,
tha ration of the molecular formula should be divided by whole number to get the simplest ratio of molecule
C₂H₆O₂ Consist of Carbon (C), Hydrogen (H), and Oxygen (O)
Now
Look at the ratio of these three atoms in the compound
C : H : O
2 : 6 : 2
Divide the ratio by two to get simplest ratio
C : H : O
2/2 : 6/2 : 2/2
1 : 3 : 1
So for the empirical formula the simplest ratio of carbon to hydrogen to oxygen is 1:3:1
So the empirical formula will be
Empirical formula of C₂H₆O₂ = CH₃O
Answer:
All three solutions have the same boiling point.
Explanation:
Elevation in boiling point is a colligative property. A colligative property depends upon the number of solute molecules irrespective of nature or molecular weight etc.
As all the given solutes (in all the three solutions) are non ionic (will not dissociate into ions) so with same molality (moles per unit Kg) they will have same number of molecules. And thus all the three aqueous solutions will have same boiling point.
Answer:
(a). With fewer molecules in the container, the molecules have lower average speeds.
(b). With fewer molecules per unit volume, the molecules hit the walls of the container less often.
(c). With lower average speeds, on average the molecules hit the walls of the container with less force.
Explanation:
Ideal gas law is given as;
PV = nRT
![P = \frac{n}{V}RT](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7Bn%7D%7BV%7DRT)
Where;
P is the pressure of the gas
V is the volume of the gas
n is the number of moles of the gas (amount of gas )
R is ideal gas constant
T is the temperature of the gas
If the amount of gas is decreased, while the volume and temperature are held constant, the pressure will decrease because number of gas moles per unit volume
will be reduced, causing the entropy of the gas to be reduced since entropy decreases with decrease in gas molecules.
As the entropy of the gas molecules reduce, the average speed of the gas molecules will be reduced as well, this will cause fewer collision of the gas molecules with the walls of the container ( i.e on average the gas molecules hit the walls of the container with less force since force is directly proportional to speed, and less force implies less pressure since the contact surface is constant).
Choosing all that apply:
- (a). With fewer molecules in the container, the molecules have lower average speeds.
- (b). With fewer molecules per unit volume, the molecules hit the walls of the container less often.
- (c) . With lower average speeds, on average the molecules hit the walls of the container with less force.
Explanation:
₁₄Si 1s²2s²2p⁶3s²3p².
Principal quantum number (n=3) have four electrons (3s²3p²).
2) ₁₉K 1s²2s²2p⁶3s²3p⁶4s¹.
Azimuthal quantum number (l=o) have seven electrons (1s²2s²3s²4s¹).
3) ₈₀Hg [Xe] 4f¹⁴5d¹⁰6s².
Principal quantum number (n=4) have thirty-two electrons (4s²4p⁶4d¹⁰4f¹⁴).
The principal quantum number is one of four quantum numbers which are assigned to each electron in an atom to describe that electron's state.
The azimuthal quantum number is a quantum number for an atomic orbital that determines its orbital angular momentum and describes the shape of the orbital.
Answer: The specific heat capacity of chromium is ![2010J/g^0C](https://tex.z-dn.net/?f=2010J%2Fg%5E0C)
Explanation:
![heat_{absorbed}=heat_{released}](https://tex.z-dn.net/?f=heat_%7Babsorbed%7D%3Dheat_%7Breleased%7D)
As we know that,
![Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})](https://tex.z-dn.net/?f=Q%3Dm%5Ctimes%20c%5Ctimes%20%5CDelta%20T%3Dm%5Ctimes%20c%5Ctimes%20%28T_%7Bfinal%7D-T_%7Binitial%7D%29)
.................(1)
where,
q = heat absorbed or released
= mass of chromium = 15.5 g
= mass of water = 55.5 g
= final temperature =![18.9^0C](https://tex.z-dn.net/?f=18.9%5E0C)
= temperature of chromium = ![100^oC](https://tex.z-dn.net/?f=100%5EoC)
= temperature of water = ![16.50^oC](https://tex.z-dn.net/?f=16.50%5EoC)
= specific heat of chromium= ?
= specific heat of water= ![4.184J/g^0C](https://tex.z-dn.net/?f=4.184J%2Fg%5E0C)
Now put all the given values in equation (1), we get
![-15.5\times c_1\times (19.5-18.9)=[55.5\times 4.184\times (19.5-100)]](https://tex.z-dn.net/?f=-15.5%5Ctimes%20c_1%5Ctimes%20%2819.5-18.9%29%3D%5B55.5%5Ctimes%204.184%5Ctimes%20%2819.5-100%29%5D)
![c_1=2010J/g^0C](https://tex.z-dn.net/?f=c_1%3D2010J%2Fg%5E0C)
The specific heat capacity of chromium is ![2010J/g^0C](https://tex.z-dn.net/?f=2010J%2Fg%5E0C)