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2 years ago

Describe the sequence of events in the formation of an evaporite

1 answer:

3 0

- Water enter from creeks, bringing whatever material it has dissolved in its way

- The materials is being build up throughout time in the lake or sea, causing its salinity to increase

- when this saline solution is evaporated, the ions in the water precipitate, forming an evaporite
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N2O5 decomposes to form NO2 and O2 with first-order kinetics. The initial concentration of N2O5 is 3.0 M and the reaction runs f

kow [346]

Answer : The final concentration of $N_2O_5$ is, 2.9 M

Explanation :

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $5.89\times 10^{-3}\text{ min}^{-1}$

t = time passed by the sample = 3.5 min

a = initial concentration of the reactant = 3.0 M

a - x = concentration left after decay process = ?

Now put all the given values in above equation, we get

$3.5=\frac{2.303}{5.89\times 10^{-3}}\log\frac{3.0}{a-x}$

$a-x=2.9M$

Thus, the final concentration of $N_2O_5$ is, 2.9 M

3 0

2 years ago

If a helium filled ballon has a volume of 3.4l at 25°c and 1.18atm., what is its volume at STP?

vladimir2022 [97]

Answer:

3.711 L

Explanation:

The formula you need to use is the following:

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\$

3.4L / 298 K = V2 / 273 K

V2 = 3.711 L

5 0

1 year ago

Which of the following are examples of physical properties of ethanol? Select all that apply.

bazaltina [42]

Ethanol is: flammable, liquid at room temperature, the boiling point is 78.37 ° C.

7 0

1 year ago

Atoms of Ca and F would be expected to react in a ratio of

Gemiola [76]

Answer:

A 1:1

Explanation:

i thinks it's right

5 0

2 years ago

Predict the boiling point of water at a pressure of 1.5 atm.

Lina20 [59]

Answer:

100.8 °C

Explanation:

The Clausius-clapeyron equation is:

$ln\frac{P_{1} }{P_{2}} =$ -Δ $\frac{H_{vap}}{r} (\frac{1}{T_{2}}-\frac{1}{T_{1}} )$

Where 'ΔHvap' is the enthalpy of vaporization; 'R' is the molar gas constant (8.314 j/mol); 'T1' is the temperature at the pressure 'P1' and 'T2' is the temperature at the pressure 'P2'

Isolating for T2 gives:

$T_{2}=(\frac{1}{T_{1}} -\frac{Rln\frac{P_{2}}{P_{1}} }{Delta H_{vap}}$

(sorry for 'deltaHvap' I can not input symbols into equations)

thus T2=100.8 °C

7 0

2 years ago