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butalik [34]
3 years ago
12

Explain about neutrinos and anti-neutrinos in about 300 words.

Chemistry
1 answer:
tankabanditka [31]3 years ago
5 0
A antiparticle known as the antineutrino is created to correspond to each neutrino (an elementary particle which is electrically neutral ) . The antineutron has a half integer spin but doesn’t have an electric charge. These are given off by the neutrino and have the opposite chirality as well as portraying leptons numbers of the opposite signs. Although neutrino’s are elementary particles they have a smaller mass than what a particle should be.

So sorry this is under 100 (no where near 300) but I guess it could start you off and adding in a few extra words would add to the total of 71? Words
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in the event of a submarine disaster the___ can be used to rescue people from the depth up to 3500 feet.
gulaghasi [49]
DSVR because it only makes sense. Try it out and if it works give me a Brainly


6 0
2 years ago
Read 2 more answers
How many milliliters of 0. 0140 m na2s2o3 solution are needed to dissolve 0. 590 g of agbr? agbr(s) 2na2s2o3(aq)→na3ag(s2o3)2(aq
Marina86 [1]

The molarity of the solution can be used to give the moles and the volume of the solution. The 0.0140 M sodium thiosulfate needs 225 ml of volume.

<h3>What is molarity?</h3>

Molarity is the property of the solution that is given by the ratio of the moles of the solute to the volume of the solution in liters.

Given,

Molarity of Sodium thiosulfate = 0.0140 M

Mass of solute (AgBr) = 0.590 gm

Molar mass of AgBr = 187.77 g/mol

First moles from the mass can be calculated as,

Moles = mass ÷ molar mass

n = 0.590 g ÷ 187.77 g/mol

= 0.00314 moles

Now, the volume of the solution from molarity is calculated as,

Volume = moles ÷ molarity

= 0.00314 moles ÷ 0.0140

= 0.225 L

Therefore, 225 mL is the volume required.

Learn more about molarity here:

brainly.com/question/13889022

#SPJ4

3 0
1 year ago
How many moles of O2 are needed to react completely with 35.0 mol C2h2
Wittaler [7]

Hey There!:


2 C2H2 + 5 O2 = 4 CO2 + 2 H2O


2 moles C2H2 ----------- 5 moles O2

35.0 moles C2H2 ------- moles O2


moles O2 = 35.0 * 5 / 2


moles O2 = 87.5 moles


hope this helps!

6 0
2 years ago
Compound A is an organic compound which contains Carbon, Hydrogen and Oxygen. When 0.240g of the vapour of A is slowly passed ov
vesna_86 [32]

(a)   In this section, give your answers to three decimal places.

(i)

Calculate the mass of carbon present in 0.352 g of CO

2

.

Use this value to calculate the amount, in moles, of carbon atoms present in 0.240 g

of

A

.

(ii)

Calculate the mass of hydrogen present in 0.144 g of H

2

O.

Use this value to calculate the amount, in moles, of hydrogen atoms present in 0.240 g

of

A

.

(iii)

Use your answers to calculate the mass of oxygen present in 0.240 g of

A

Use this value to calculate the amount, in moles, of oxygen atoms present in 0.240 g

of

A


(b)

Use your answers to

(a)

to calculate the empirical formula of

A


thank you

hope it helpsss

4 0
3 years ago
What is Mg + O2 —&gt; MgO
Agata [3.3K]

Answer:

this is a oxidation reaction

product is magnesium oxide

the balanced equation is

2Mg + O2 -> 2MgO

5 0
3 years ago
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