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3 years ago

How does specific heat affect the rate at which an object changes temperature

2 answers:

OverLord2011 [107]3 years ago

6 0

<span>How does specific heat affect the rate at which an object changes temperature </span>All else being equal,* rate of heat transfer is proportional to the square of the temp difference between source and sink. Given a step change in input, heat transfer will change abruptly; then the rate of transfer will gradually decrease as source and sink temperatures approach each other. Ideally the rate of transfer will go asymptotically to zero as the source and sink attain equal temperatures. In a real system it will go to some stable minimum as heat leaks in/out in various directions.

<span>Since a sink with lower thermal capacity (specific heat x mass) will require less heat input for a given temperature change, heat transfer in such a system will drop off more quickly than it would in one with higher thermal capacity -- the reverse of what you're proposing. At the same time, the system will reach steady-state faster because there's less total heat in the system. </span>

Once a system has stabilized in steady-state, thermal capacity is no longer an issue.

stira [4]3 years ago

5 0

If it is lower, it heats faster, if it's higher, it takes longer to heat.

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In a local bar, a customer slides an empty beer mug down the counter for a refill. The height of the counter is 1.42 m. The mug

telo118 [61]

Answer:

a) $V_{x}=3.72m/s$ , b) ∠=-54.83°

Explanation:

In order to solve this problem, we must start with a drawing of the situation, this will help us visualize the problem better. (See picture attached).

Now, the idea is that the beer mug has a horizontal speed and no vertical speed at initial conditions. So knowing this, we can start finding the initial velocity of the mug.

In order to do so, we need to find the time it takes for the mug to reach the ground. We can find it by using the following equation:

$y=y_{0}+V_{y0}t+\frac{1}{2}a_{y}t^{2}$

We can see from the drawing that y and the initial velocity in y are zero, so we can simplify our formula:

$0=y_{0}+\frac{1}{2}a_{y}t^{2}$

so we can solve for t, so we get:

$t=\sqrt{\frac{-(2)y_{0}}{a}}$

so now we can substitute the known values, so we get:

$t=\sqrt{\frac{-(2)(1.42)}{-9.8}}$

which yields:

t=0.538s

So we can use this value to find the velocity in x:

$V_{x}=\frac{x}{t}$

When substituting we get:

$V_{x}=\frac{2m}{0.538s}$

which yields:

$V_{x}=3.72m/s$

In order to solve part b, we need to find the y-component of the velocity, for which we can use the following formula:

$\Delta y=\frac{V_{f}^{2}-V_{0}^{2}}{2a}$

We know that $V_{0}$ is zero, so we can simplify the expression:

$\Delta y=\frac{V_{yf}^{2}}{2a}$

So we can solve the equation for $V_{yf}^{2}$ so we get:

$V_{yf}=\sqrt{2\Delta y a}$

and when substituting the known values we get:

$V_{yf}=\sqrt{2(-1.42m)(-9.8m/s^{2})}$

which yields:

$V_{yf}=-5.28m/s$

Once we got the final velocity in y, we can use it together with the velocity in x to find the angle.

So we can use the following formula:

$tan \theta =\frac{V_{y}}{V_{x}}$

when solving for theta we get:

$\theta = tan^{-1}(\frac{V_{y}}{V_{x}})$

We can substitute so we get:

$\theta = tan^{-1}(\frac{-5.28m/s}{3.72m/s})$

which yields:

$\theta = -54.83^{o}$

7 0

3 years ago

Before starting this problem, review Conceptual Example 3 in your text. Suppose that the hail described there comes straight dow

bulgar [2K]

Answer:

0.9 N

Explanation:

The force exerted on an object is related to its change in momentum by:

$F=\frac{\Delta p}{\Delta t}$

where

F is the force exerted

$\Delta p$ is the change in momentum

$\Delta t$ is the time interval

The change in momentum can be rewritten as

$\Delta p = m(v-u)$

where

m is the mass

u is the initial velocity

v is the final velocity

So the formula can be rewritten as

$F=\frac{m(v-u)}{\Delta t}$

In this problem we have:

$\frac{m}{\Delta t}=0.030 kg/s$ is the mass rate

$u=-15 m/s$ is the initial velocity

$v=+15 m/s$ is the final velocity

Therefore, the force exerted by the hail on the roof is:

$F=(0.030)(+15-(-15))=0.9 N$

6 0

3 years ago

What is the correct answer?

inysia [295]

The answer to your question is metaphase

3 0

3 years ago

Atoms are known to form charges due to their ability to gain and lose electrons in reactions. As a result, atoms

galben [10]

Answer:

C. Fe: 24 electrons

Explanation:

From the analogy given, the atom with a charge of +2 is Fe having 24 electrons.

To calculate the charges on an atom;

Number of charges = Number of protons - Number of electrons.

O: 10 electrons: 8 protons = 8 - 10 = -2

N: 10 electrons; 7 protons = 7 - 10 = -3

Cl: 18 electrons; 17 protons = 17 - 18 = -1

So;

Fe: 24 electrons and 26 protons = 26 -24 = +2

Therefore, the solution is Fe

7 0

3 years ago

The direction of an electric field is the direction (5 points) a negative test charge will move in the field a positive test cha

svet-max [94.6K]

Answer:

a positive test charge will move in the field

Explanation:

The direction of an electric field corresponds to the direction of motion of a positive test charge in the electric field. In fact:

- the electric field produced by a positive charge points outwards the charge --> this is because when a positive test charge is placed in this field, it will feel a repulsive force (because two positive charges repel each other), so it will move away from the positive charge that produces the field

- the electric field produced by a negative charge points towards the charge itself--> this is because when a positive test charge is placed in this field, it will feel an attractive force (because a positive and a negative charge attract each other), so it will move toward the negative charge that produces the field.

4 0

3 years ago