All categories

4 years ago

How does the law of inertia relate to how the planets in our solar system revolve around the sun?

Physics

1 answer:

Alekssandra [29.7K]4 years ago

4 0

Answer:

The law of inertia relates to revolution of planets round the sun due to constant motion of the planets round the sun.

Explanation:

Law of inertia states that a body at rest or uniform motion will continue to be at rest or uniform motion unless it is acted upon by an external force.

The gravitational force keeps the planets revolving round the sun in a uniform motion, this will continue till infinity unless equal and opposite force acts on our planets.

Therefore, the law of inertia relates to revolution of planets round the sun due to constant motion of the planets round the sun.

You might be interested in

A research student wants to know whether ethanol is a better fuel than gasoline. Which step in the process of scientific inquiry

DerKrebs [107]

Answer:

Asking a scientific question

Explanation:

4 0

3 years ago

Read 2 more answers

A miniature quadcopter is located at x = -2.25 m and y, - 5.70 matt - 0 and moves with an average velocity having components Vv,

kupik [55]

Recall that average velocity is equal to change in position over a given time interval,

$\vec v_{\rm ave} = \dfrac{\Delta \vec r}{\Delta t}$

so that the x-component of $\vec v_{\rm ave}$ is

$\dfrac{x_2 - (-2.25\,\mathrm m)}{1.60\,\mathrm s} = 2.70\dfrac{\rm m}{\rm s}$

and its y-component is

$\dfrac{y_2 - 5.70\,\mathrm m}{1.60\,\mathrm s} = -2.50\dfrac{\rm m}{\rm s}$

Solve for $x_2$ and $y_2$ , which are the x- and y-components of the copter's position vector after t = 1.60 s.

$x_2 = -2.25\,\mathrm m + \left(2.70\dfrac{\rm m}{\rm s}\right)(1.60\,\mathrm s) \implies \boxed{x_2 = 2.07\,\mathrm m}$

$y_2 = 5.70\,\mathrm m + \left(-2.50\dfrac{\rm m}{\rm s}\right)(1.60\,\mathrm s) \implies \boxed{y_2 = 1.70\,\mathrm m}$

Note that I'm reading the given details as

$x_1 = -2.25\,\mathrm m \\\\ y_1 = -5.70\,\mathrm m \\\\ v_x = 2.70\dfrac{\rm m}{\rm s}\\\\ v_y=-2.50\dfrac{\rm m}{\rm s}$

so if any of these are incorrect, you should make the appropriate adjustments to the work above.

8 0

3 years ago

Which of the following statements is TRUE about impulse? (Consider the Impulse-Momentum Theorem: F▲t = m ▲v )

kotykmax [81]

The statement “Impulse is a vector quantity” is true about Impulse.

Answer: Option B

Explanation:

The object’s action by applied force in a particular time interval, there happens changing in momentum called impulse. It is denoted by a symbol ‘J’ or ‘imp’ and expressed in a unit ‘Ns’. As impulse depends on the acted force, when a collision arises from front, behind or side, the force’s direction would be differed.

$\text {Impulse }=\text {Force } \times \text {time}=\vec{F} \Delta t$

So, from this option A is false as impulse is not a force but changing momentum. The unit is not Newton, it is Newton second (Ns). The force direction differs (impulse direction) for each cases of collision, so option D also false. Hence, option B seems to be correct. Vector quantity deals with both direction and magnitude and important in motion study.

8 0

3 years ago

PLEASE HELP THIS IS DUE TODAY If an element's atomic mass and atomic number are known, what else can be determined? Give an exam

Fudgin [204]

If you know an element’s atomic number, you will learn the number of protons and electrons. The atomic number is equal to the number or protons and electrons. You can also find the number of neutrons, by subtracting the atomic mass from the atomic number.

For example, Fluorine’s atomic number is 9, and its atomic mass is 19. So, the number of electrons and protons in fluorine is 9. The number of neutrons the is equal to 19-9. Thus, Fluorine has 10 neutrons.

Hope this helps :)

4 0

3 years ago

Proof of conservation of energy

frutty [35]

If you compare the energy at two different times in an equation, you'll see no difference, because it's been conserved. The total energy of a system is the sum of its energy in motion - its kinetic energy - and its energy due to its position, which is its potential energy

6 0

3 years ago