Answer:
The answer to your question is P2 = 84.16 kPa
Explanation:
Data
Volume 1 = V1 = 4.52 L Volume 2 = V2 = 4.83 l
Pressure 1 = P1 = 102 kPa Pressure 2 = P2 = ?
Temperature 1 = T1 = 23°C Temperature 2 = T2 = -12°C
Process
1.- Convert the temperature to °K
Temperature 1 = 23 + 273 = 296°K
Temperature 2 = -12 + 273 = 261°K
2.- Use the Combined Gas law to solve this problem
P1V1/T1 = P2V2/T2
-Solve for P2
P2 = P1V1T2 / T1V2
-Substitution
P2 = (102)(4.52)(261) / (296)(4.83)
-Simplification
P2 = 120331.44 / 1429.68
-Result
P2 = 84.16 kPa
Answer : The net ionic equation will be,

Explanation :
In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.
The balanced ionic equation between zinc and hydrochloric acid will be,

The ionic equation in separated aqueous solution will be,

In this equation,
is the spectator ion.
By removing the spectator ion from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,

Answer:
1109 g H₂O
Explanation:
2.2 pounds can be converted to grams using a conversion ratio:
(2.2lb)(453.592g/lb) = 997.9024 g C₅₇H₁₁₀O₆
The mass in grams is converted to moles using the molecular weight of tristearin (891.48 g/mol)
(997.9024 g)(mol/891.48g) = 1.119...mol C₅₇H₁₁₀O₆
The moles of C₅₇H₁₁₀O₆ can be related to the moles of water through the molar ratio:
(1.119mol C₅₇H₁₁₀O₆)(110 H₂O/2 C₅₇H₁₁₀O₆) = 61.545 mol H₂O
The mass of water is then calculated using the molecular weight (18.02 g/mol):
(61.545 mol)(18.02 g/mol) = 1109 g H₂O
Answer: Concentration of
at equilibrium = 0.08 M
Concentration of
at equilibrium =0.08 M
Concentration of
= 0.64M
Explanation:
Moles of
= 4.00 mole
Volume of solution = 5.00 L
Initial concentration of
=
Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as 
For the given chemical reaction:

Initial conc. 0.8 M 0 M 0 M
At eqm. conc. (0.8-2x) M (x) M (x) M
The expression for
is written as:
![K_c=\frac{[H_2]^1[I_2]^1}{[HI]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BH_2%5D%5E1%5BI_2%5D%5E1%7D%7B%5BHI%5D%5E2%7D)


Concentration of
at equilibrium = x M = 0.08 M
Concentration of
at equilibrium = x M = 0.08 M
Concentration of
= (0.8-2x) = 
Answer:
Se + 2e- => Se-2
Explanation:
Ions are electrically charged particles, formed due to the gain or loss of electrons by an atom.
There are two types of ions cations and anions. An element that loses their electrons and forms positive ions are cations while metals and element that gains one or more electrons and forms negative ions are anions.
Selenium is an atom with atomic number 34 and represented as Se. The electronic configuration of Se is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p4. Selenium will gain 2 more electrons to complete it p orbital and form an ion Se-2.
The equation is as below:
Se + 2e- => Se-2