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Galina-37 [17]
3 years ago
15

PLEASE HELP!!!

Chemistry
2 answers:
Natalija [7]3 years ago
8 0

Answer:

aaaaaaaaaa bbbbbccccddddeeeffffggghhhhiiijjjkkkklllmmmnnnnooppppqqqqqrrrssstttuuuuvvvvvwwwwwyyyyxxxxxttttuuuuuuvvvvv

Explanation:

julsineya [31]3 years ago
7 0
A wet barometer puts a vacuum above a liquid and applies air pressure to the surface of the liquid - the height of the liquid above to reservoir surface is the measure of air pressure. The liquid can be in a J tube with an open end or a straight tube in a pool. Air pressure will support about 30" of mercury or about 32 feet of water. 
<span>A dry barometer uses a sealed chamber with a diaphragm with a lever touching it or a spiral tube with a link connected to a display needle. In the former, the slight movement of the diaphragm with changed pressure is translated to a large movement of the end of the lever movement across the scale. In the spiral, the expanding/contracting air inside the tube changes its shape and pulls the needle over. </span>
<span>In both case, the scale of pressure for the needle has to be calibrated to the design. </span>
<span>- </span>
<span>How Tropical Cyclones are Observed </span>
<span>* Direct measurements of tropical storm and hurricane dimensions and wind speeds are taken primarily by reconnaissance </span>
<span>aircraft, although ships and buoys also take important measurements. Once a hurricane is near and/or on land, Automated </span>
<span>Surface Observation Systems (ASOS) provide surface conditions, and radio sondes take upper air measurements. </span>
<span>* Indirect observational methods include satellite imagery and Doppler radar. In particular, satellites have greatly improved </span>
<span>our ability to monitor and understand hurricanes. Radar data are important once the storm comes close to shore </span>
<span>and after landfall for forecasting hurricane-related weather. </span>

<span>I hope this is helpful.</span>
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Empirical formula of a compound composed of 32.1 g potassium (k) and 6.57 g oxygen (o)?
tester [92]

The empirical formula is K₂O.

The empirical formula is the <em>simplest whole-number ratio</em> of atoms in a compound.

The <em>ratio of atom</em>s is the same as the <em>ratio of moles</em>.

So, our job is to calculate the <em>molar ratio</em> of K to O.

Step 1. Calculate the <em>moles of each element </em>

Moles of K = 32.1 g K × (1 mol K/(39.10 g K =) = 0.8210 mol K

Moles of O = 6.57 g O × (1 mol O/16.00 g O) = 0.4106 mol 0

Step 2. Calculate the <em>molar ratio of each elemen</em>t

Divide each number by the smallest number of moles and round off to an integer

K:O = 0.8210:0.4106 = 1.999:1 ≈ 2:1

Step 3: Write the <em>empirical formula </em>

EF = K₂O

5 0
3 years ago
Consider the reaction directly below and answer parts a and b. C6H4(OH)2 (l) + H2O2 (l) à C6H4O2 (l) + 2 H2O (l)
dedylja [7]

Answer:

a. -206,4kJ

b. Surroundings will gain heat.

c. -115kJ are given off.

Explanation:

It is possible to obtain ΔH of a reaction using Hess's law that consist in sum the different ΔH's of other reactions until obtain the reaction you need.

Using:

<em>(1) </em>C₆H₄(OH)₂(l) → C₆H₄O₂(l) + H₂(g) ΔH: +177.4 kJ

<em>(2) </em>H₂(g) + O₂(g) → H₂O₂ (l) ΔH: -187.8 kJ

<em>(3) </em>H₂(g) + 1/2O₂(g) → H₂O(l) ΔH: -285.8 kJ

It is possible to obtain:

C₆H₄(OH)₂(l) + H₂O₂(l) → C₆H₄O₂(l) + 2H₂O(l)

From (1)-(2)+2×(3). That is:

<em>(1) </em>C₆H₄(OH)₂(l) → C₆H₄O₂(l) + H₂(g) ΔH: +177.4 kJ

<em>-(2) </em>H₂O₂(l) → H₂(g) + O₂(g) ΔH: +187.8 kJ

<em>2x(3) </em>2H₂(g) + O₂(g) → 2H₂O(l) ΔH: 2×-285.8 kJ

The ΔH you obtain is:

+177,4kJ + 187,8kJ - 2×285.8 kJ =<em> -206,4kJ</em>

b. When ΔH of a reaction is <0, the reaction is exothermic, that means that the reaction produce heat and the <em>surroundings will gain this heat.</em>

c. 20,0g of H₂O are:

20,0g×\frac{1mol}{18,01g} = <em>1,11 mol H₂O</em>

As 2 moles of H₂O are produced when -206,4kJ are given off, when 1,11mol of H₂O are produced, there are given off:

1,11mol H₂O×\frac{-206,4kJ}{2mol} =<em> -115kJ</em>

I hope it helps!

8 0
3 years ago
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