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Galina-37 [17]
4 years ago
15

PLEASE HELP!!!

Chemistry
2 answers:
Natalija [7]4 years ago
8 0

Answer:

aaaaaaaaaa bbbbbccccddddeeeffffggghhhhiiijjjkkkklllmmmnnnnooppppqqqqqrrrssstttuuuuvvvvvwwwwwyyyyxxxxxttttuuuuuuvvvvv

Explanation:

julsineya [31]4 years ago
7 0
A wet barometer puts a vacuum above a liquid and applies air pressure to the surface of the liquid - the height of the liquid above to reservoir surface is the measure of air pressure. The liquid can be in a J tube with an open end or a straight tube in a pool. Air pressure will support about 30" of mercury or about 32 feet of water. 
<span>A dry barometer uses a sealed chamber with a diaphragm with a lever touching it or a spiral tube with a link connected to a display needle. In the former, the slight movement of the diaphragm with changed pressure is translated to a large movement of the end of the lever movement across the scale. In the spiral, the expanding/contracting air inside the tube changes its shape and pulls the needle over. </span>
<span>In both case, the scale of pressure for the needle has to be calibrated to the design. </span>
<span>- </span>
<span>How Tropical Cyclones are Observed </span>
<span>* Direct measurements of tropical storm and hurricane dimensions and wind speeds are taken primarily by reconnaissance </span>
<span>aircraft, although ships and buoys also take important measurements. Once a hurricane is near and/or on land, Automated </span>
<span>Surface Observation Systems (ASOS) provide surface conditions, and radio sondes take upper air measurements. </span>
<span>* Indirect observational methods include satellite imagery and Doppler radar. In particular, satellites have greatly improved </span>
<span>our ability to monitor and understand hurricanes. Radar data are important once the storm comes close to shore </span>
<span>and after landfall for forecasting hurricane-related weather. </span>

<span>I hope this is helpful.</span>
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6th grade math help me plz (don’t take from internet write in ur own words)
lapo4ka [179]

Answer:

An independent variable is changed and used to test what would happen to the dependent if changed. Dependent variables are always staying the same.

Explanation:

4 0
3 years ago
Read 2 more answers
Gallium is produced by the electrolysis of a solution obtained by dissolving gallium oxide in concentrated NaOH(aq). Calculate t
Alina [70]

<u>Answer:</u> The mass of gallium produced by the electrolysis is 0.0354 grams.

<u>Explanation:</u>

The equation for the deposition of Ga(s) from Ga(III) solution follows:

Ga^{3+}(aq.)+3e^-\rightarrow Ga(s)

  • To calculate the total charge, we use the equation:

C=I\times t

where,

C = charge

I = current = 0.490 A

t = time required (in seconds) = 50\times 60=300s    (Conversion factor: 1 min = 60 s)

Putting values in above equation, we get:

C=0.490\times 300=147C

  • To calculate the moles of electrons, we use the equation:

\text{Moles of electrons}=\frac{C}{F}

where,

C = charge = 147 C

F = Faradays constant = 96500

\text{Moles of electrons}=\frac{147}{96500}=1.52\times 10^{-3}mol

  • Now, to calculate the moles of gallium, we use the equation:

\text{Moles of Gallium}=\frac{\text{Moles of electrons}}{n}

where,

n = number of electrons transferred = 3

Putting values in above equation, we get:

\text{Moles of Gallium}=\frac{1.52\times 10^{-3}}{3}=5.077\times 10^{-4}mol

  • To calculate the mass of gallium, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of Gallium = 5.077\times 10^{-4}mol

Molar mass of Gallium = 69.72 g/mol

Putting values in above equation, we get:

5.077\times 10^{-4}mol=\frac{\text{Mass of Gallium}}{69.72g/mol}\\\\\text{Mass of Gallium}=0.0354g

Hence, the mass of gallium produced by the electrolysis is 0.0354 grams.

8 0
3 years ago
Hydrazine (N2H4) emits a large quantity of
azamat

Answer:

              1.75 moles of H₂O

Solution:

The Balance Chemical Equation is as follow,

                                   N₂H₄  +  O₂    →    N₂  +  2 H₂O

Step 1: Calculate the Limiting Reagent,

According to Balance equation,

             32.04 g (1 mol) N₂H₄ reacts with  =  32 g (1 mol) of O₂

So,

                   28 g of N₂H₄ will react with  =  X g of O₂

Solving for X,

                       X  =  (28 g × 32 g) ÷ 32.04 g

                       X  =  27.96 g of O₂

It means 29 g of N₂H₄ requires 47.96 g of O₂, while we are provided with 73 g of O₂ which is in excess. Therefore, N₂H₄ is the limiting reagent and will control the yield of products.

Step 2: Calculate moles of Water produced,

According to equation,

            32.04 g (1 mol) of N₂H₄ produces  =  2 moles of H₂O

So,

                        28 g of N₂H₄ will produce  =  X moles of H₂O

Solving for X,

                      X  =  (28 g × 2 mol) ÷ 32.04 g

                      X  =  1.75 moles of H₂O

5 0
4 years ago
Iodine-131 has a half-life of 8 days. If you have 8 g of I-131 and 16 days pass, how much I-131 do you have left?
alexandr1967 [171]

Answer:

2g

Explanation:

2 half-lives will pass. Therefore the amount will be quartered into 2g.

3 0
3 years ago
PLEASE HELP ASAP
Kisachek [45]

Answer:

opg

Explanation:

A series of chemical reactions transform Volatile Organic Compounds (VOCs) into substances that combine with nitrogen dioxide to produce PAN (Peroxyacytyl nitrate), yet another element in smog. Nitrogen dioxide in the air also reacts with water vapor to form nitric acid, one of the types of acid in acid rain.

6 0
3 years ago
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