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Novay_Z [31]
2 years ago
6

Why did the flame of the burning match or splint go out sodium carbonate and hcl?

Chemistry
1 answer:
Alexandra [31]2 years ago
6 0
<span>The flame goes out on a burning match when sodium carbonate and hydrochloric

</span>
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The property of metals to be made into wire is called
ANEK [815]

Metal have some properties like lustrous (shiny), good conductors of electricity and heat,etc. Metals have another property by which metal can be drawn into a wire by hammering on it .This property is called as 'ductility'.

hope this helps, please mark brainliest. :)

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2 years ago
.Inherited traits are passed from parent to offspring by information coded in
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Inherited traits are passed from parent to offspring by information coded in

the DNA or Deoxyribonucleic Acid

8 0
3 years ago
How many moles are in 15.0 grams of calcium (Ca)?
borishaifa [10]
1 mol ---- 40g
X --------- 15g
X = 15/40 = 0,375 moles

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5 0
2 years ago
Read 2 more answers
If the molecules in the above illustration react to form NH3 according to the equation N2 3 H2 2 NH3 , the limiting reagent is ,
Kamila [148]

Answer:

Follows are the solution to these question:

Explanation:

Given equation:

N_2+3H_2 \longrightarrow 2NH_3

In this equation:

1 N_2 gives = 2NH_3

so,

3N_2 gives=  2 \times 3 = 6 NH_3

similarly:

3H_2 gives = 2NH_3

So, 6H_2 gives = \frac{2}{3}\times 6=4NH_3

Its limited reagent is =N_2

The amount of NH_3 molecules were formed = 4.

and the amount of  H_2 excess molecules are= 1

8 0
2 years ago
The half-life of the first-order decay of radioac- . 14C . b l:Ive 1s a out 5720 years. Calculate the rate constant for the reac
Alinara [238K]

Answer:

a. Rate constant: 1.2118x10⁻⁴ yrs⁻¹

b. The age of the object is 20750 years

Explanation:

a. We can solve the rate constant in an isotope decay by using Half-Life, as follows:

K = Ln 2 / Half-life

K = ln 2 / 5720 years =

<h3>1.2118x10⁻⁴ yrs⁻¹</h3><h3 />

b. The general equation of isotope decay is:

Ln [A] = -kt + Ln [A]₀

<em>Where [A] is concentration of the isotope after time t, </em>

<em>k is rate constant</em>

<em>and [A]₀ initial concentration of the isotope.</em>

<em />

Computing the values of the problem:

Ln [0.89x10⁻¹⁴] = -1.2118x10⁻⁴ yrs⁻¹t + Ln [1.1x10⁻¹³]

-2.5144 = -1.2118x10⁻⁴ yrs⁻¹t

20750 years = t

The age of the object is 20750 years

<em />

4 0
2 years ago
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