For [Ca +2 ]:
0.0010 mol/l · 0.05 l =
For [ SO4 -2 ] :
0.01 mol/l · 0.05 l =
Cumulative volume:
50 ml + 50 ml = 10 ml = 0.1 l
[Ca +2 ] =
[SO4 - 2] =
Qc for CaSO4:
Qc =
This is less than Ksp of CaSO4.
Answer:
C ) No precipitation will occur.
Answer:
Explanation:
From the given information;
Let Q(t) = mass of dye in the tank as a function of time
The mass in the tank = 200 L × (1g/L) = 200 g
Using the law of mass conservation;
Q(0) = 200
By finding the solution to the ODE using the method of separation of variables;
Using the initial condition;
200 = Q(0) = C
1% of 200g = 2g of dye solution
∴
t = 460.5 hours
1st you pour the mixture<span> through a filter to remove the larger </span>pebbles<span>. Next, add water to dissolve the salt and then filter out the </span>pepper the last thing you do <span>evaporate the water to leave the salt behind.</span>