All categories

3 years ago

A 5 kg mass is oscillating on a spring with a time period of 2.8 seconds. What is the spring constant k of the spring?

Physics

1 answer:

katrin [286]3 years ago

5 0

Answer:

k = 25.18 N/m

Explanation:

Simple Harmonic Oscillator

It consists of a weight attached to one end of a spring being allowed to move forth and back.

If m is the mass of the weight and k is the constant of the spring, the period of the oscillation is given by:

$\displaystyle T=2\pi {\sqrt {\frac {m}{k}}}$

If the period is known, we can find the value of the constant by solving for k:

$\displaystyle k=m\left(\frac{2\pi}{T}\right)^2$

Substituting the given values m=5 Kg and T=2.8 seconds:

$\displaystyle k=5 \left(\frac{2\pi}{2.8}\right)^2$

k = 25.18 N/m

You might be interested in

A long jumper can jump a distance of 7.4 m when he takes off at an angle of 45° with respect to the horizontal. Assuming he can

GenaCL600 [577]

Answer:

0.02 m

Explanation:

R₁ = initial distance jumped by jumper = 7.4 m

R₂ = final distance jumped by jumper = ?

θ₁ = initial angle of jump = 45°

θ₂ = final angle of jump = 42.9°

$v$ = speed at which jumper jumps at all time

initial distance jumped is given as

$R_{1}=\frac{v^{2}Sin2\theta _{1} }{g}$

final distance jumped is given as

$R_{2}=\frac{v^{2}Sin2\theta _{2} }{g}$

Dividing final distance by initial distance

$\frac{R_{2}}{R_{1}}=\frac{Sin2\theta _{1}}{Sin2\theta _{2}}$

$\frac{R_{2}}{7.4}=\frac{Sin2(42.9)}{Sin2(45))}$

$R_{2} =7.38$

distance lost is given as

d = $R_{1} - R_{2}$

d = 7.4 - 7.38

d = 0.02 m

8 0

3 years ago

6. Aaron will run from home at y mph and walk back at x mph. how much distance does he need to travel to spend a total of t hour

Kisachek [45]

Answer:

Total distance, $d=\dfrac{xyt}{(x+y)}$

Explanation:

It is given that,

Speed of Aaron from home is y mph and walk back at x mph. Let t is the total time he spend in walking and jogging. Let d is the distance covered.

We he moves from home to destination, time is equal to, $\dfrac{d}{x}$

Similarly, when he move back to home, time taken is equal to $\dfrac{d}{y}$

Total time taken is equal to :

$\dfrac{d}{x}+\dfrac{d}{y}=t$

$d(\dfrac{1}{x}+\dfrac{1}{y})=t$

$d=\dfrac{t}{(\dfrac{1}{x}+\dfrac{1}{y})}$

$d=\dfrac{xyt}{(x+y)}$

So, the distance he speed in walking and jogging is $\dfrac{xyt}{(x+y)}$ . Hence, this is the required solution.

8 0

3 years ago

Iron has a density of 7.9 g/cm3. What is the mass of a cube of iron with the length of one side equal to 55.0 mm?

saw5 [17]

Density is a value for mass, such as kg, divided by a value for volume, such as m3. Density is a physical property of a substance that represents the mass of that substance per unit volume. To find the mass of the substance, we need to multiply the volume occupied by the substance.

Mass = Density x Volume
Mass = 7.9 g/cm^3 (5.5 cm)^3
Mass = 43.45 g

4 0

3 years ago

Read 2 more answers

Two massive particles with identical charge are launched into the uniform field between two plates from the same launch point wi

Svetach [21]

<h2>Answernswe:</h2>

<h2>The interaction between charged object is a non-contact force that acts over some distance of separation.Charge,charge and distance.Every electrical interaction involves a force that highlights the importance of these three variables</h2>

6 0

3 years ago

An object, whose mass is 0.660 kg, is attached to a spring with a force constant of 132 N/m. The object rests upon a frictionles

Arada [10]

Answer:

See below

Explanation:

a) Spring force at release = k * d = 132 N/m * .120 m = 15.84 N

b) F = ma

15.84 = (.660 kg)(a) a = 24 m/s^2

c) Toward the left ....the object is accelerated to the left

7 0

1 year ago