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Brut [27]
2 years ago
7

Calculate the pressure of 2.50 Liters of a gas at 25.0oC if it has a volume of 4.50 Liters at

Chemistry
1 answer:
MariettaO [177]2 years ago
4 0

Answer:

P_2 =0.51  atm

Explanation:

Given that:

Volume (V1) = 2.50 L

Temperature (T1) = 298 K

Volume (V2) = 4.50 L

at standard temperature and pressure;

Pressure (P1) = 1 atm

Temperature (T2) = 273 K

Pressure P2 = ??

Using combined gas law:

\dfrac{P_1V_1}{T_1} = \dfrac{P_2V_2}{T_2} \\ \\ \dfrac{1 *2.5}{298} = \dfrac{P_2*4.5}{273}

0.008389261745 \times 273 = 4.5P_2

P_2 =\dfrac{0.008389261745 \times 273 }{4.5}

P_2 =0.51 \ atm

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Answer:

Im pretty sure you use mass

Explanation:

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3 years ago
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The following is known as the thermite reaction: 2Al(s)+Fe2O3(s)→Al2O3(s)+2Fe(s) This highly exothermic reaction is used for wel
Colt1911 [192]

Answer:

\Delta H_{rxn}=-847.6\ KJ/mol.

Explanation:

The balanced chemical equation is:

2Al(s)+Fe_2O_3(s)-->Al_2O_3+2Fe(s)

Now, standard values of \Delta H_f\ of\ all\ participants\ of\ reaction.

\Delta H_f(Al_2O_3)=-1669.8\ KJ/mol\\\Delta H_f(Fe_2O_3)=-822.2\ KJ/mol\\\Delta H_f(Al(s))=0\ KJ/mol\\\Delta H_f(Fe(s))=0\ KJ/mol\\

Now, We know \Delta H_{rxn}=\Delta H_{products}-\Delta H_{reactants}

Putting all values of \Delta H_f to above equation.

We get,

\Delta H_{rxn}=-847.6\ KJ/mol.

Hence, this is the required solution.

6 0
3 years ago
A reaction mechanism is defined as the sequence of reaction steps that define the pathway from reactants to products. Each step
olga55 [171]

Answer: (a) K *[A][B]^2

(b) The answer is B

Explanation:

A)

Step1:A+B<--> C (fast)

Step2: B+C→D(slow)

Rate depends on slowest step.

so,

rate = k' [B][C] ...eqn 1

But C is intermediate.so use step 1

Since 1st step is an equilibrium,

Kc = [C] /[A][B]

so,

[C] = Kc [A][B] ...eqn 2

put eqn 2 in eqn 1

rate = k' *[B] * Kc [A][B]

= k'Kc*[A][B]^2

= K *[A][B]^2 {writing k'Kc = K}

Answer: K *[A][B]^2

B)

Answer is B

Since rate depends on slowest step.

if slowest step is:

X2Y2+Z2→X2Y2Z+Z

then only,

rate= k[X2Y2][Z2]

Answer: B

6 0
3 years ago
A sample of nitrogen gas collected at a pressure of 1.03 atm and a temperature of 279 K is found to occupy a volume of 568 milli
DIA [1.3K]

Answer: 0.025 moles of nitrogen gas are there in the sample.

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1.03 atm

V = Volume of gas = 568 ml = 0.568 L   (1L=1000ml)

n = number of moles  = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =279K

n=\frac{PV}{RT}

n=\frac{1.03atm\times 0.568L}{0.0821L atm/K mol\times 279K}=0.025moles

0.025 moles of nitrogen gas are there in the sample.

4 0
3 years ago
Suppose a platinum atom in the oxidation state formed a complex with two chloride anions and two ammonia molecules. Write the ch
Korolek [52]

Answer: Pt(Cl)2(NH3)2

Explanation:

In the formation of the complex, the oxidation number of platinum is plus two (+2) and two chloride ions cancel it out by their oxidation number of -1 each. Hence the complex has an overall charge of zero. It is thus neutral with no charge attached to its formula.

7 0
3 years ago
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