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dem82 [27]
3 years ago
14

A computational model predicts the maximum potential energy a roller coaster car can have given its mass and its speed at the lo

west point of its journey. Its mass is 350 kg, and it speed at a height of 0 m is 25 m/s. What is the prediction for its maximum potential energy?
109,375 J

765,625 J

218,750 J

87,750 J
Physics
1 answer:
andreyandreev [35.5K]3 years ago
3 0

Answer:

The prediction for its maximum potential energy is 109,375 J

Explanation:

Given;

mass of the coaster car, m = 350 kg

speed of the coaster car at the lowest point, v = 25 m/s

The coaster car will have maximum kinetic energy at the lowest point and based on law of conservation of mechanical energy, the maximum kinetic energy of the coaster car at the lowest point will be equal to maximum potential energy at the highest point.

K.E_{max} = P.E_{max}

K.E_{max} = \frac{1}{2} mv^2\\\\K.E_{max} = \frac{1}{2} (350)(25)^2\\\\K.E_{max} =109,375 \ J

Thus, P.E_{max} = 109,375 \ J

Therefore, the prediction for its maximum potential energy is 109,375 J

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Rutherford discovered the nucleus of the atom by firing a particles at gold foil. An a particle has a charge of q = +2e and a ma
Readme [11.4K]

Answer:r_0=3.037\times 10^{-14}m

Explanation:

Given

charge on alpha particle=+2e

mass of alpha particle=6.64\times 10^{-27} kg

Charge on gold nucleus=+79e

Velocity at r=1m is 1.9\times 10^{7}

Using Energy conservation

Kinetic energy of particle will be converting to Potential energy as it approaches to nucleus

therefore

\frac{1}{2}mv^2+U_{r=1m}=U_{closest\ to\ nucleus}

\frac{1}{2}\left ( 6.64\times 10^{-27}\right )\left ( 1.9\times 10^{7}^2\right )+\frac{K\left ( 2e\right )\left ( 79e\right )}{1}=\frac{K\left ( 2e\right )\left ( 79e\right )}{r_0}

\frac{1}{2}\left ( 6.64\times 10^{-27}\right )\left ( 1.9\times 10^{7}^2\right )=\frac{9\times 10^9\times 158\times \left ( 1.6\times 10^{-19}\right )}{y}\left [\frac{1}{r_0}-\frac{1}{1}\right ]

on solving we get

\frac{1}{r_0}=3.292\times 10^{13}

r_0=3.037\times 10^{-14}m

8 0
3 years ago
Newton's law of universal gravitation, the law of conservation of mass, the law of superposition, and the laws of thermodynamics
Llana [10]

Answer:

D

Explanation:

There are no exceptions to these laws under specific stated conditions..

The laws of science are statements that describe or predict a range of phenomena as they appear in nature. Laws explain facts determined by experiment. Laws do not have absolute certainty and be changed by future experiments and observations.

5 0
3 years ago
A pick-up truck with two passengers weighs about 14000 N. In good driving conditions around a curve, the maximum friction with t
Zolol [24]

Answer:

85.14 m

Explanation:

Let g = 9.81 m/s2. We can find the truck mass from its weight

m = W/g = 14000 / 9.81 = 1427 kg

So if the maximum friction could be the truck weight, which is F = 14000N, then that would also be the maximum centripetal force it could be. According to Newton 2nd law of motion, the maximum centripetal acceleration the truck can have when traveling at a curve is

a = F / m = 14000 / 1427 = 9.81 m/s2

By applying the following formula we can find the minimum safe radius R of the curve when traveling at speed of 28.9 m/s

a = \frac{v^2}{R}

R = \frac{v^2}{a} = \frac{28.9^2}{9.81} = 85.14 m

6 0
3 years ago
A cat runs 11 m east and then turns around and runs 30 m west. What is the cat's total
Vadim26 [7]

The cat's displacement is 19 m west.

8 0
3 years ago
A car is traveling at speed of 18.6m/s and entering a 12m wide intersection when the light has 0.582seconds More Time remain yel
Marrrta [24]

Answer:

6.94 m/s²

Explanation:

Given that:

Initial Velocity (u) = 18.6 m/s

Time, t = 0.582

S, distance = 12 m

S = ut + 0.5at²

12 = (18.6 * 0.582) + 0.5(a)(0.582²)

12 = 10.8252 + 0.169362a

12 - 10.8252 = 0.169362a

1.1748 = 0.169362a

a = 1.1748 / 0.169362

a = 6.9366209

a = 6.94 m/s²

Hence, acceliofbthe car should be 6.94 m/s²

4 0
3 years ago
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