Answer:
A. Rock fragments are layered and pressurized over time.
Explanation:
Sedimentary rocks are derived from pre-existing rocks that have been subjected to agents of denudation, weathered, transported and deposited within a basin.
In the basin, the sediments are accumulated in their final resting position.
- Sediments are accumulated as layers on top of one another.
- The pressure of the sediment on top of another forces out water and presses the layers into sheets.
- Over time, the compression leads to lithification of the rock.
- During lithification, compaction and cementation occurs.
Answer:
150 g/mol
Explanation:
Let's consider the complete neutralization of a diprotic acid H₂X with NaOH.
H₂X + 2 NaOH → Na₂X + 2 H₂O
40.0 mL of 0.200 M NaOH. were required to reach the endpoint. The reacting moles of NaOH are:
0.0400 L × 0.200 mol/L = 8.00 × 10⁻³ mol
The molar ratio of H₂X to NaOH is 1:2. The reacting moles of H₂X are 1/2 × 8.00 × 10⁻³ mol = 4.00 × 10⁻³ mol.
4.00 × 10⁻³ moles of H₂X have a mass of 0.600 g. The molar mass of H₂X is:
0.600 g/4.00 × 10⁻³ mol = 150 g/mol
I attached the working and the answer to both questions below.
Please note that E = energy, ν = frequency, h = Plank's Constant
<span>The energy of a 4.66 x 10</span>¹⁴<span> Hz wave is
3.088 </span>
× <span>
10</span>
⁻¹⁷ J
Answer: We take 20 ml of 1.0 M fruit drink and add 80 ml of water to get 100 ml of 0.2 M solution.
Explanation:
According to the neutralization law,
where,
= molarity of stock solution = 0.2 M
= volume of stock solution = 100 ml
= molarity of resulting solution = 1.0 M
= volume of resulting solution = ?
Now put all the given values in the above law, we get the volume of resulting solution.
Therefore, the volume of 1.0 M required is 20 ml.
We take 20 ml of 1.0 M fruit drink and add 80 ml of water to get 100 ml of 0.2 M solution.
Answer:
120 gram sample of a radioactive element, how many grams of that element will be left after 3 half-lives have passed? If you have a 300
Explanation:
Hope this helps!
