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2 years ago

Which statement correctly describes the relationship between thermal energy and particle movement?

1 answer:

5 0

As thermal energy increases, there is more particle movement. As thermal energy increases, there is more particle movement. As thermal energy increases, there is less particle movement.

Sure hope this helps you

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A single-phase electrical load draws 600KVA at 0.6 power factor lagging. a) Find the real and reactive power absorbed by the loa

Whitepunk [10]

Answer:

(a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

Explanation:

Given that,

Power factor = 0.6

Power = 600 kVA

(a). We need to calculate the reactive power

Using formula of reactive power

$Q=P\tan\phi$ ...(I)

We need to calculate the $\phi$

Using formula of $\phi$

$\phi=\cos^{-1}(Power\ factor)$

Put the value into the formula

$\phi=\cos^{-1}(0.6)$

$\phi=53.13^{\circ}$

Put the value of Φ in equation (I)

$Q=600\tan(53.13)$

$Q=799.99\ kVAR$

(b). We draw the power triangle

(c). We need to calculate the reactive power of a capacitor to be connected across the load to raise the power factor to 0.95

Using formula of reactive power

$Q'=600\tan(0.95)$

$Q'=9.94\ KVAR$

We need to calculate the difference between Q and Q'

$Q''=Q-Q'$

Put the value into the formula

$Q''=799.99-9.94$

$Q''=790.05\ KVAR$

Hence, (a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

8 0

3 years ago

Fill in the blank .Technically color consists of electromagnetic _____

8_murik_8 [283]

Electromagnetic radiation

5 0

3 years ago

A uniform rod of length 50cm and mass 0.2kg is placed on a fulcrum at a distance of 40cm from the left end of the rod. At what d

Aleks04 [339]

I’m pretty sure it’s b

8 0

3 years ago

A 300-W blender did 10,500J of work. how long was the blender running?

forsale [732]

Answer:

The blender was running for 35 seconds.

Explanation:

Given:

Power of the blender is, $P=300\ W$

Work done by the blender is, $W=10500\ J$

We know that, power is defined as the rate at which work is done by the body.

Here, we are given the power and work done and we are asked to find time taken.

Let the time of running of the blender be 't' seconds.

So, the power of the blender is given as:

$P=\frac{W}{t}$

Rewriting the above in terms of 't', we have

$t=\frac{W}{P}$

Plug in the given values and solve for 't'. This gives,

$t=\frac{10500}{300}\\t=35\ s$

Therefore, the blender was running for 35 seconds.

6 0

3 years ago

Please Help ASAP!!!⚠️⚠️

Bad White [126]

Given :

A map shows that a star is 25 light years away.

To Find :

If you get in a ship and travel to this star at 0.95c, How far will the ship need to travel to reach this star.

Solution :

We know, 1 light year in km is given by :

$1 \ light \ years = 9.46 \times 10^{12}\ km$

So, 25 light years is given by :

$25 \ light \ years = 25 \times 9.46 \times 10^{12}\ km\\\\25 \ light \ years = 2.365 \times 10^{14} \ km$

Hence, this is the required solution.

8 0

2 years ago