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liberstina [14]
3 years ago
11

Kinetic friction acts on a baseball player sliding into first base. Will the player's velocity change?

Physics
1 answer:
Law Incorporation [45]3 years ago
7 0
Yes, his velocity will decrease the further he slides.
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Hi i need help pls help me
r-ruslan [8.4K]
The correct answer would be the last one
4 0
2 years ago
Read 2 more answers
At the local hockey rink, a puck with a mass of 0.12kg is given an initial speed of 5.3m/s. If the coefficient of friction betwe
Salsk061 [2.6K]
Here’s my work to your question. I used Newton’s Second Law and a kinematics equation to arrive at the answer.

5 0
2 years ago
A Ray of light in air is incident on an air to glass boundary at an angle of 30. degrees with the normal. If the index of refrac
elena55 [62]

Answer:

A

Explanation:

Snell's law states:

n₁ sin θ₁ = n₂ sin θ₂

where n is the index of refraction and θ is the angle of incidence (relative to the normal).

The index of refraction of air is approximately 1.  So:

1 sin 30° = 1.52 sin θ

θ ≈ 19°

5 0
3 years ago
The pressure gauge shown below has a spring for which k = 60 N/m, and the area of the piston is 0.50 cm2. Its right end is conne
kicyunya [14]

Answer:

0.025 m

0.059166 m

Explanation:

P = Pressure

A = Area

x = Compression of spring

Force is given by

F=PA\\\Rightarrow F=30000\times 0.5\times 10^{-4}\\\Rightarrow F=1.5\ N

From Hooke's law

F=kx\\\Rightarrow x=\dfrac{F}{k}\\\Rightarrow x=\dfrac{1.5}{60}\\\Rightarrow x=0.025\ m

The spring is compressed 0.025 m

In the second case

F_1=1.5\ N

F_2=101000\times 0.5\times 10^{-4}\\\Rightarrow F_2=5.05\ N

Net force would be

F=F_2-F_1\\\Rightarrow F=5.05-1.5\\\Rightarrow F=3.55\ N

Compression would be

x=\dfrac{F}{k}\\\Rightarrow x=\dfrac{3.55}{60}\\\Rightarrow x=0.059167\ m

The compression of the spring is 0.059166 m

8 0
3 years ago
On a farm, you are pushing on a stubborn pig with a constant horizontal force with magnitude 30.0 n and direction 37.0° counterc
sashaice [31]

<span>Since the force is applied at an angle from the horizontal, we will use the horizontal component of this force in calculating for the displacements.
From derivation, the Fx is:</span>

Fx = F cos φ

Where:

Fx = is the horizontal component of the force

F = total force

φ = angle in radian = 37 * pi / 180 = 0.645 rad

Calculating: Fx = 30.0 N * cos(0.645)

Fx = 23.97 N = 24 N

Calculating for Work: W = Fx * d

A. W = 24 N * 15 m = 360 N

B. W = 24 N * 16 m = 384 N

C. W = 24 N * 12 m = 288 N

D. W = 24 N * 14 m = 336 N 

8 0
2 years ago
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