Answer:
The partial pressure of Helium is 275.7 torr
The partial pressure of argon is 457.3 torr
The total pressure is 733 torr
Explanation:
Step 1: Data given
Volume helium flask = 275 mL = 0.275L
Pressure in helium flask = 752 torr
Volume argon flask = 475 mL = 0.475 L
Pressure in argon flask = 722 torr
Step 2: Calculate the total volume of the gas mixture once the stopcock is opened.
Total volume = volume of Helium flask + volume argon flask
Total volume = 275 + 475 = 750 mL = 0.750 L
Step 3: Calculate partial pressure of Helium
pHe *VHe = p'He * Vtotal
⇒ with pHe = the pressure of Helium = 752 torr
⇒ with VHe = the volume in the helium flask = 275 mL
⇒ with p'He = the partial pressure of helium = To be determined
⇒with Vtotal = the total volume = 750 mL
p'He = (pHe*VHe)/Vtotal
p'He = (752*275)/750
p'He = 275.7 torr
Step 4: Calculate partial pressure of Argon
pAr *VAr = p'Ar * Vtotal
⇒ with pAr = the pressure of Argon = 722 torr
⇒ with VAr = the volume in the Argon flask = 475 mL
⇒ with p'Ar = the partial pressure of argon = To be determined
⇒with Vtotal = the total volume = 750 mL
p'Ar = (pAr * VAr)/Vtotal
p'Ar = (722*475)/750
p'Ar = 457.3 torr
Step 5: Calculate the total pressure
Total pressure = partial pressure Helium + partial pressure Argon
Total pressure = 275.7 torr + 457.3 torr = 733 torr
