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lesantik [10]
4 years ago
7

The______ of a sound wave is defined as the amount of energy passing through a unit area of the wave front in a unit of time

Physics
1 answer:
poizon [28]4 years ago
4 0
The intensity of a sound wave is defined as the amount of energy passing through a unit area of the wave front in unit of time.
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10. A 90 kg box is sliding across a surface at a constant velocity while experiencing a rightward applied
ANEK [815]

If the box is moving at constant velocity, net force must be zero, so:

F + fr = 0

fr = -F

<u>fr = -40 N</u>

4 0
3 years ago
Read 2 more answers
A 15.0-Ω resistor and a coil are connected in series with a 6.30-V battery with negligible internal resistance and a closed swit
Aloiza [94]

Answer:

0.04328 H

0.00288 seconds

0.01326 seconds

Explanation:

V = Voltage = 6.3 V

R = Resistance = 15 Ω

L = Inductance

I = Decayed current = 0.21 A

t = Time to decay = 2 ms

Maximum Current is given by

I_0=\frac{V}{R}\\\Rightarrow I_0=\frac{6.3}{15}\\\Rightarrow I_0=0.42\ A

Current in the circuit is given by

I=I_0exp\frac{-Rt}{L}\\\Rightarrow ln\frac{I_0}{I}=\frac{Rt}{L}\\\Rightarrow L=\frac{Rt}{ln\frac{I_0}{I}}\\\Rightarrow L=\frac{15\times 2\times 10^{-3}}{ln\frac{0.42}{0.21}}\\\Rightarrow L=0.04328\ H

The inductance is 0.04328 H

Time constant is given by

\tau=\frac{L}{R}\\\Rightarrow \tau=\frac{0.04328}{15}\\\Rightarrow \tau=0.00288\ s

Time constant is 0.00288 seconds

Time required is given by

t=\tau ln\frac{I_0}{I}\\\Rightarrow t=0.00288\times ln\frac{I_0}{0.01I_0}\\\Rightarrow t=0.01326\ s

The time to reach 1% of its original value is 0.01326 seconds

7 0
4 years ago
1. A 2.10 m rope attaches a tire to an overhanging tree limb. A girl swinging on the
Alecsey [184]

Answer:

29.6 kg

Explanation:

Centripetal force = mass × centripetal acceleration

F = m v² / r

88.0 N = m (2.50 m/s)² / 2.10 m

m = 29.6 kg

5 0
3 years ago
Help please
pav-90 [236]

Air is a mixture.

as per definition, mixture is a combination we get after adding two or more things together in any proportion.

air is a mixture because it contains a number of gases like nitrogen , oxygen, carbon dioxide. it also contains dust particles, small organisms, water vapors etc.

carbon monoxide is not a mixture as it is formed from fixed proportion of carbon and oxygen.

similarly, water is is not a mixture as it is formed from fixed proportion of hydrogen and oxygen.

8 0
3 years ago
Read 2 more answers
A 6.0-kg object moving at 5.0 m/s collides with and sticks to a 2.0-kg object. After the collision the composite object is movin
gogolik [260]

Answer:

a) 23 m/s

Explanation:

  • Assuming no external forces acting during the collision, total momentum must be conserved, as follows:

       p_{o} = p_{f}  (1)

  • The initial momentum p₀, can be written as follows:

       p_{o} =  m_{1}  * v_{1o} + m_{2}* v_{2o} =   6.0 kg * 5.0 m/s + 2.0 kg * v_{2o}  (2)

  • The final momentum pf, can be written as follows:

        p_{f} = (m_{1} + m_{2} )* v_{f}  = 8.0 kg* (-2.0 m/s)  (3)

  • Since (2) and (3) are equal each other, we can solve for the only unknown that remains, v₂₀, as follows:

       v_{2o} = \frac{-6.0kg* 5m/s -8.0 kg*2.0m/s}{2.0kg}  = \frac{-46kg*m/s}{2.0kg} = -23.0 m/s  (4)

  • This means that the 2.0-kg object was moving at 23 m/s in a direction opposite to the 6.0-kg object, so its initial speed, before the collision, was 23.0 m/s.
6 0
3 years ago
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