Amount of moles of water is 4.36 mol
Explanation: M(C2H2) = 2·12.01 + 2·1.008 = 26.036 g/mol
Amount of substance is n= m/M= 56.8 g / 26.036 g/mol= 2.18159 mol
Water is needed 2·2.18 mol = 4.36 mol
Answer:
A, option is the correct answer of this question
Answer:
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The number of moles present in 29.5 grams of argon is 0.74 mole.
The atomic mass of argon is given as;
Ar = 39.95 g/mole
The number of moles present in 29.5 grams of argon is calculated as follows;
39.95 g ------------------------------- 1 mole
29.5 g ------------------------------ ?

Thus, the number of moles present in 29.5 grams of argon is 0.74 mole.
<em>"Your question seems to be missing the correct symbol for the element" </em>
Argon = Ar
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