Answer: 110000
Explanation:
26/9=30.5555555556
30.5555555556 x 60=1833.33333333
110000 x 60=110000
The solution would be like
this for this specific problem:
<span>
The force on m is:</span>
<span>
GMm / x^2 + Gm(2m) / L^2 = 2[Gm (2m) / L^2] ->
1
The force on 2m is:</span>
<span>
GM(2m) / (L - x)^2 + Gm(2m) / L^2 = 2[Gm (2m) / L^2]
-> 2
From (1), you’ll get M = 2mx^2 / L^2 and from
(2) you get M = m(L - x)^2 / L^2
Since the Ms are the same, then
2mx^2 / L^2 = m(L - x)^2 / L^2
2x^2 = (L - x)^2
xsqrt2 = L - x
x(1 + sqrt2) = L
x = L / (sqrt2 + 1) From here, we rationalize.
x = L(sqrt2 - 1) / (sqrt2 + 1)(sqrt2 - 1)
x = L(sqrt2 - 1) / (2 - 1)
x = L(sqrt2 - 1) </span>
= 0.414L
<span>Therefore, the third particle should be located the 0.414L x
axis so that the magnitude of the gravitational force on both particle 1 and
particle 2 doubles.</span>
Answer:
Temperature will be 305 K
Explanation:
We have given The asteroid has a surface area ![A=7.70m^2](https://tex.z-dn.net/?f=A%3D7.70m%5E2)
Power absorbed P = 3800 watt
Boltzmann constant ![\sigma =5.67\times 10^{-8}Wm/K^4](https://tex.z-dn.net/?f=%5Csigma%20%3D5.67%5Ctimes%2010%5E%7B-8%7DWm%2FK%5E4)
According to Boltzmann rule power radiated is given by
![P=\sigma AT^4](https://tex.z-dn.net/?f=P%3D%5Csigma%20AT%5E4)
![3800=5.67\times 10^{-8}\times 7.70\times T^4](https://tex.z-dn.net/?f=3800%3D5.67%5Ctimes%2010%5E%7B-8%7D%5Ctimes%207.70%5Ctimes%20T%5E4)
![T^4=87.0381\times 10^8](https://tex.z-dn.net/?f=T%5E4%3D87.0381%5Ctimes%2010%5E8)
![T=305K](https://tex.z-dn.net/?f=T%3D305K)
So temperature will be 305 K
Answer:
4.88 m/s
Explanation:
Vertical component would be 12 * sin 24 = 4.88 m/s
Horizontal is 12 * cos 24
The major characteristic an organic compound has which an inorganic
compound doesn't have is the presence of carbon atoms in the molecule.
This helps us to differentiate the compounds into their respective divisions.
Inorganic compounds
Organic compounds
We can observe that inorganic compounds lack carbon atoms which makes
the answer valid.
Read more about inorganic compounds on brainly.com/question/2169750