Answer:
Percent error = -22%
Explanation:
Given data:
Density of aluminium = 2.1,2.12 and 2.09 g/cm³
Accepted value of density of aluminium = 2.7 g.cm³
Percent error = ?
Solution:
First of all we will calculate the average of data measured by students.
Average value = 2.1 g/cm³ + 2.12 g/cm³+ 2.09 g/cm³ / 3
Average value = 6.31 g/cm³/ 3
Average value = 2.1 g/cm³
Now we will calculate the percent error.
Percent error = [ Measured value - accepted value / accepted value ]× 100
Percent error = [ 2.1 g/cm³ - 2.70 g/cm³ / 2.70 g/cm³ ]× 100
Percent error = [-0.6/2.70 g/cm³ ] × 100
Percent error = -0.22 × 100
Percent error = -22%
Explanation:
The temperature at which vapor pressure of a liquid becomes equal to the atmospheric pressure is known as boiling point.
At the boiling point the liquid and vapor state of a substance remains in equilibrium till the time all molecules of liquid do not turn into vapor.
When all the liquid molecules change into vapor state then only there will occur a rise in temperature.
Properties that do not depend on the amount of matter are known as intensive properties.
For example, boiling point, melting point, density etc.
On the other hand, properties which depend on the amount of matter are called extensive properties.
For example, volume, density etc.
Thus, we can conclude that if you heat a liquid and measure the temperature at which it boils, you are measuring an intensive property.
It isn't balanced. You have 3 *H and 3 * O, so something in the first formula must be changed. Have been searching for 1 hour and can't find the answer.
Sorry this is late but I will cause energy transformation
hope this helps :))
Answer:
that results in an alcohol and a carboxylic acid.
Explanation:
Saponification is a chemical reaction process of alkaline hydrolysis of esters(R'COOR group) by which soap is obtained.
For Example, when a base such as sodium hydroxide [NaOH] is used to hydrolyze an ester, the products are a carboxylate salt and an alcohol. Because soaps are prepared by the alkaline hydrolysis of fats and oils.
In a saponification reaction, alkaline hydrolysis of fats and oils with sodium hydroxide yields propane-1,2,3-triol and the corresponding sodium salts of the component fatty acids.
i.e Fat or oil + caustic alkali ⇒ Soap + propane-1,2,3-triol
As a specific example, ethyl acetate and NaOH react to form sodium acetate and ethanol:
The reaction goes to completion in the image below:
