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beks73 [17]
3 years ago
9

When magnesium carbonate, mgco2, reacts with nitric acid, hno3, magnesium nitrate and carbonic acid form. carbonic acid then bre

aks down into water and carbon dioxide. what two types of reactions take place in this process?
Chemistry
2 answers:
drek231 [11]3 years ago
7 0

Explanation:

Magnesium carbonate reacts with nitric acid to give magnesium nitrate and carbonic acid.

MgCO_3(aq)+2HNO_3(aq)\rightarrow Mg(NO_3)_2(aq)+H_2CO_3(aq)

This type of reaction is termed as double displacement reaction, in which ions of compounds changes their positions with each other to produce the new products.

H_2CO_3(aq)\rightarrow H_2O(l)+CO_2(g)

This type of reaction is termed as decomposition reaction, in which a compound breaks down into two or more smaller compounds.

Svetllana [295]3 years ago
5 0
Double-replacement and decomposition. (C)
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Use the unbalanced equation NH3+O2=NO+H2O to find the mole ratio between NO and H2O
Leona [35]

Answer:

For every 4 moles of NO created, 6 moles of H2O are created so the ratio is 4:6

Explanation:

You just need to balance the equation.

NH3 + O2 -> NO + H2O

1. I started with hydrogen; there's 3 on the left and 2 on the right. Multiply them together to find a number they both go into (3×2=6, but in this case 6 hydrogen on each side does not work so I doubled it so there is 12 hydrogen on each side).

This will bring you to this:

4NH3 + O2 -> NO + 6H2O

2. Now get equal amounts of nitrogen on each side. There's 4 nitrogen on the left side, and 1 on the right. Multiply the right by 4. Then you will have this:

4NH3 + O2 -> 4NO + 6H2O

3. Last thing you need to do is have the same amount of oxygen on both sides. On the left you have 2 and on the right you have 10. Get the left to 10 by multiplying it by 5.

Balanced: 4NH3 + 5O2 -> 4NO + 6H2O

In word form, for every reaction between 4 moles of ammonia and 5 moles of oxygen, 4 moles of nitric oxide and 6 moles of water will be created.

I hope this helps!

5 0
3 years ago
To what temperature must a balloon, initially at 25°c and 2.00 l, be heated in order to have a volume of 6.00 l?
Kaylis [27]
V1 = 2.00 L 
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<span>T2 = ? </span>
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<span>V1/T1 = V2/T2 </span>
<span>T2 = T1V2/V1 = (298)(6)/(2) = 894 deg K</span>
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