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1 year ago

How did planck find the correct curve for the specturm of light emitted by a hot obkect?

1 answer:

3 0

Planck find the correct curve for the specturm of light emitted by a hot object by vibrational energies of the atomic resonators were quantized.

<h3>Briefing :</h3>

The energy density of a black body between λ and λ + dλ is the energy E=hc/λ of a mode times the density of states for photons, times the probability that the mode is occupied.
This is Planck's renowned equation for a black body's energy density.
According to this, electromagnetic radiation from heated bodies emits in discrete energy units or quanta, the size of which depends on a fundamental physical constant (Planck's constant). The basis of infrared imaging is the correlation between spectral emissivity, temperature, and radiant energy, which is made possible by Planck's equation.

Learn more about the Planck's constant with the help of the given link:

brainly.com/question/27389304

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A 10kg box accelerates forward at a rate of 12 m/s^2. What is the force acting on the box?

Allushta [10]

Answer:

120N

Explanation:

Newton's second law formula: F= ma

given that m = 10 kg, a = 12 m/s^2

F = ma = 10 kg * 12 m/s^2 = 120 kgm/s^2 = 120 N

5 0

2 years ago

A train moving with a velocity of 42.9 km/hour North, increases its speed with a uniform acceleration of 0.250 m/s^2 North until

ankoles [38]

Answer:

3658.24m

Explanation:

Hello!

the first thing that we must be clear about is that the train moves with constant acceleration

A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.

When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.

$\frac {Vf^{2}-Vo^2}{2.a} =X$

Vf = final speed =160km/h=44.4m/s

Vo = Initial speed =42.9km/h=11.92m/s

A = acceleration =0.25m/s^2

X = displacement

solving

$\frac {44.4^{2}-11.92^2}{2.(0.25)} =X\\X=3658.24m$

the distance traveled by the train is 3658.24m

5 0

3 years ago

Two blocks are connected as shown in the diagram below. Assume that the ramp is frictionless. Draw the force diagram for the blo

cluponka [151]

Answer:

diagram: see image, x-component: 84.3 N, acceleration: 4.38 m/s^2

Explanation:

(see image for further explanation)

5 0

3 years ago

What is the velocity of a quarter drooped from a towards after 10secounds

ArbitrLikvidat [17]

U=0
<span>t=10 </span>
<span>a=9.8m/s/s </span>
<span>v is velocity (the tower must be very high to be able to fall for 10 seconds!!!) </span>

<span>you work out the result now</span>

6 0

2 years ago

Two objects, A and B, are in contact with one another. Initially, the temperature of A is 50 °C and the temperature of B is 100

V125BC [204]

Answer:

Explanation:

because kinetic energy is directly proportional to temperature so the hottor the object, the more kinetic energy.

6 0

3 years ago