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ludmilkaskok [199]
2 years ago
11

What is the substance of ossenburger’s speech?

Chemistry
1 answer:
Nonamiya [84]2 years ago
6 0

Holden was thinking that the only good part of his speech was the middle part of it. He was talking about what a swell and hot-shot guy he was, that's what I think.
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How many moles of ag are formed by the complete reaction of 28.3 mol of pb?
levacccp [35]
<span>Answer: 56.6 moles Explanation: 28.3 moles of Pb would produce twice as much moles as Ag. 28.3 X (2moles Ag/ 1 mol Pb) = 56.6 moles of Ag.</span>
4 0
3 years ago
A recipe calls for 1.2 cups of oil. How many liters of oil is this?
Nadusha1986 [10]
.3 liters... im pretty sure this is correct!!
3 0
3 years ago
Read 2 more answers
Using the Brønsted-Lowry concept of acids and bases, identify the Brønsted-Lowry acid and base in each of the following reaction
Luden [163]

Answer:

1. HSO³⁻(aq) + H₂O(l) → H₂SO₃(aq) + OH⁻(aq)

<u>The Brønsted-Lowry acid is H₂O and the Brønsted-Lowry base is HSO³⁻</u>

<u />

2. (CH₃)₃N(g) + BCl₃(g) → (CH₃)₃NBCl₃(s)

<u>There are no Brønsted-Lowry acids and bases in this reaction.</u>

Explanation:

According to the Brønsted-Lowry concept, when an acid (HA) and a base (B) undergoes a chemical reaction, the acid (HA) loses a proton and forms its conjugate base (A⁻), whereas the base gains (B) the proton to form its conjugate acid (HB⁺).

<em>The chemical equation for this reaction is:</em>

HA  +  B  ⇌  A⁻  +  HB⁺

Given reactions:

1. HSO³⁻(aq) + H₂O(l) → H₂SO₃(aq) + OH⁻(aq)

<u>The Brønsted-Lowry acid is H₂O and the Brønsted-Lowry base is HSO³⁻</u>

Reason: In this reaction, the acid H₂O loses a proton and forms its conjugate base, OH⁻. Whereas, the base HSO³⁻ gains a proton to form its conjugate acid, H₂SO₃.

2. (CH₃)₃N(g) + BCl₃(g) → (CH₃)₃NBCl₃(s)

<u>There are no Brønsted-Lowry acids and bases in this reaction.</u>

Reason: In this reaction, there is no exchange of proton between the acid and the base.

4 0
2 years ago
a 160 milligram sample of a radioactive isotope decays to 10 kilograms in 12 years. what is the half life of this element
Shkiper50 [21]

Answer:

3 years

Explanation:

Given data:

Initial amount of sample = 160 Kg

Amount left after 12 years = 10 Kg

Half life = ?

Solution:

at time zero = 160 Kg

1st half life = 160/2 = 80 kg

2nd half life = 80/2 = 40 kg

3rd half life = 40 / 2 = 20 kg

4th half life = 20 / 2 = 10 kg

Half life:

HL = elapsed time / half life

12 years / 4 = 3 years

8 0
3 years ago
What is the role of plastocyanin in the z-scheme model?
murzikaleks [220]

Answer:

It shuttles electrons between the cytochrome complex and photosystem I.

Explanation:

6 0
2 years ago
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