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ivann1987 [24]
4 years ago
12

Picking up a paper clip with a magnet. Physical change, Chemical change, or neither

Chemistry
1 answer:
aksik [14]4 years ago
4 0
Hello there! :D

A physical change is a change in which something is changed in appearance. For example, if I cut a piece of paper in half. 

A chemical change is when the composition (or the makeup) of something is changed. For example, baking soda and vinegar. They react to form a whole different thing. 

Picking up a paper clip with a magnet doesn't change its appearance. It doesn't change its composition. The magnet only picks up the paper clip because it attracts magnetic objects, if you were to take it off of the paper clip it would still be the same paper clip, and most likely look the same. 

I hope this helps!
~kaikers
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A student prepares a solution by combining 100 mL of 0.30 M HNO2(aq) and 100 mL of 0.30 M KNO2(a). Which of the following equati
katrin2010 [14]

Answer:

B

Explanation:

This creates a buffer solution meaning it will just neutralize out and does not change the PH massively.

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3 years ago
Pls help tysm <3 :D:D
Marianna [84]
Not sure about 2 or 3 but I believe that for number 1 is B or claim 2!!
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3 years ago
At 298 K, Kc = 1.45 for the following reaction 2 BrCl (g) Br2(g) + Cl2(g) A reaction mixture was prepared with the following ini
tester [92]

Answer:

[BrCl]=0.02934M

[Br2]=[Cl2]=0.03533M

Explanation:

First, consider the Kc definition:

1.5=K_{c}=\frac{[Br_{2}][Cl_{2}]}{[BrCl]^{2}}

It is necessary to define a new variable, 'x', as the amount of moles of Br2 that are produced. If 'x' moles of Br2 are produced, the moles of the compounds will be calculated as;

n_{Br_{2}}=n_{{Br_{2}}^{0}} +x\\n_{Cl_{2}}=n_{{Cl_{2}}^{0}} +x\\n_{BrCl}=n_{{BrCl}}^{0}} -2x\\

Where the zero superscript means the initial moles.

Dividing the last equations by the volume, which is constant because the reaction does not change the total moles number (2 moles of BrCl produce 2 moles, one of Cl2 and another of Br2), we have the molarity equations for all species:

M_{Br_{2}}=M_{{Br_{2}}^{0}} +x\\M_{Cl_{2}}=\\M_{BrCl}=M_{{BrCl}}^{0}} -2x\\

And now 'x' is a change in molarity.

Replacing these in the Kc equation we have:

1.45=\frac{({M_{{Br_{2}}}^{0}}+x)({M_{{Cl_{2}}}^{0}}+x)}{({M_{{BrCl}}^{0}}-2x)^{2}}

Where the only unknown is 'x'. So, let's solve the equation:

1.45=\frac{(0.03+x)(0.03+x)}{(0.04-2x)^{2} } \\1.45(0.04-2x)^2=(0.03+x)^2\\1.45(0.0016-0.16x+4x^2)=0.0009+0.06x+x^2\\4.8x^2-0.292x+0.00142=0\\x_{1}=0.0555\\x_{2}=0.00533

The result x_{1}=0.0555 lacks of sense because it will give a negative concentration for BrCl, so the result is x_{2}=0.00533<u>.</u>

Applying the result, the concentrations at equilibrium are:

M_{Br_{2}}=M_{Cl_{2}}=0.03+0.00533=0.03533M\\M_{BrCl}=0.04-2*0.00533=0.02934M

If you calculate Kc with this concentrations it will give 1.45 as a result.

Greets, I will be happy to solve any doubt you have.

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4 years ago
Which type of isomers are o-xylene, m-xylene, and p-
mojhsa [17]

The  o-xylene, m-xylene, and p-Xylene are constitutional isomers. The correct option is D.

<h3>What are isomers?</h3>

Isomers are the elements or polyatomic elements that have similar molecular formula.

All options are attached here:

A.optical isomers

B.structural isomers

C.geometric isomers

D.constitutional isomers

Thus, the correct option is D.constitutional isomers.

Learn more about isomers

brainly.com/question/13422357

#SPJ1

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Answer:

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