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antiseptic1488 [7]
3 years ago
14

Calculate the moles of 36.030 g of H2O.

Chemistry
1 answer:
lions [1.4K]3 years ago
4 0

Answer: 1.99 mol h20

Explanation:

you have 36.030 g, trying to get it into mols

to get from g to mols, use the molar mass (periodic table)

36.030 g h20 (1 mol/18.02g) = 1.99 mol h20

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If a solid line represents a covalent bond and a dotted line represents intermolecular attraction, which of these choices shows
blsea [12.9K]
<span>Generally, a hydrogen bond can be characterized as a proton shared by two lone electron pairs. It occurs when a hydrogen (H) atom, covalently bound to a highly electronegative atom such as nitrogen (N), oxygen (O), or fluorine (F), experiences the electrostatic field of another highly electronegative atom nearby.

   Among the choices in the bond (-N...H-O) one side of the Hydrogen is bonded to a highly electronegative atom with a lone pair (-N) and the other side is directly bonded with a highly electronegative atom (O-).

    So -N...H-O- shows a hydrogen bond.</span>
4 0
3 years ago
Molar mass is used in a conversion factor to calculate ___ and uses the units of ____.
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Answer:

The molar mass is used in a conversion factor to calculate the weight of one mole of a given compound and uses the units of grams / mole ____.

Explanation:

Se utilizan los pesos atómicos (Z) de cada componente para calcular la masa de 1 mol de compusto, ejemplo:

H20 (agua)

Masa molar H20 = (Peso atomico H) x 2 + Peso atomico 0 = 1, 007g x2 + 16g = 18 gramos / mol

4 0
3 years ago
Choose the BEST answer from the four options A, B, C, or D: Due to which property of LPG are we asked to close the valve of the
Mama L [17]

Answer:

A

Explanation:

We are usually asked to close the valve of the gas cylinder in our various kitchens at home <u>due to the inflammable property of the Liquified Petroleum Gas.</u>

<em>Without closing the valve, the LPG would diffuse into our homes, and any form of spark would cause an explosion and lead to a fire. Lives and properties could be lost in the process.</em>

The correct option is A.

4 0
2 years ago
If a tree dies and the trunk remains undisturbed for 13,750 years, what percentage of the original 14c is still present? (the ha
defon

Answer:

18.94%.

Explanation:

  • The decay of carbon-14 is a first order reaction.
  • The rate constant of the reaction (k) in a first order reaction = ln (2)/half-life = 0.693/(5730 year) = 1.21 x 10⁻⁴ year⁻¹.
  • The integration law of a first order reaction is:

<em>kt = ln [A₀]/[A]</em>

k is the rate constant = 1.21 x 10⁻⁴ year⁻¹.

t is the time = 13,750 years.

[A₀] is the initial percentage of carbon-14 = 100.0 %.

[A] is the remaining percentage of carbon-14 = ??? %.

∵ kt = ln [Ao]/[A]

∴ (1.21 x 10⁻⁴ year⁻¹)(13,750 years) = ln (100.0%)/[A]

1.664 =  ln (100.0%)/[A]

Taking exponential for both sides:

5.279 = (100.0%)/[A]

<em>∴ [A]</em> = (100.0%)/5.279 = <em>18.94%.</em>

8 0
2 years ago
By definition, any substance that donates a proton is best defined as _________.
BabaBlast [244]
A proton is the same as an H+ ion, and Arrhenius acids are the ones that release H+ in solution, so the answer is A
8 0
3 years ago
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