Answer:
a) a = 6.72 10⁻⁵ m, b) the slit (a) is smaller, which represents a wider pattern
Explanation:
In is a diffraction experiment since we have a single slit, it is explained by the equation
a sin θ = m λ
where a is the width of the slit
The diffraction pattern is characterized by a very intense central maximum, with a value of 5.0 cm, therefore the distance from the center to the first zero is y = 5.0 / 2 cm = 2.5 10⁻² m
let's use trigonometry to enter the angle
tan θ = y / L
tan θ = sin θ / cos θ = sin θ
sin θ = y / L
substituting into the equation
a y / L = m λ
the first maximum occurs for m = 1
a = λ L / y
let's calculate
a = 560 10⁻⁹ 3.0 / 2.5 10⁻²
a = 6.72 10⁻⁵ m
b) if the width a of the slit (a) is smaller
sin θ = m λ / a
therefore the sinus increases, which implies a greater angle, which represents a wider pattern
c) if the distance to the screen (L) goes away
y = m λL / a
If L increases the width of the pattern they also increase of course the intensity must be less
d) If the wavelength increases
In this case the width of the pattern also increases
e) What happens if the light passes through two slits in this case we have two diffraction patterns one centered in each slit and the resulting pattern is the sum of these patterns, this sum gives the double slit interference that characterizes a series of slits of equal height
