Answer:
mol LiCl = 4.83 m
Explanation:
GIven:
Solution of LiCl in water XLiCl = 0.0800
Mol of water in kg = 55.55 mole
Find:
Molality
Computation:
mole fraction = mol LiCl / (mol water + mol LiCl)
0.0800 = mol LiCl / (55.55 mol + mol LiCl)
0.0800 mol LiCl + 4.444 mol = mol LiCl
mol LiCl - 0.0800 mol LiCl = 4.444 mol
0.92 mol LiCl = 4.444 mol
mol LiCl = 4.83 m
Flammability
Hope it helps!
Answer:
Hey, I hope this helps. You gave the equation already balanced so there was no need to do so, the next thing we need to do after balancing is to split the strong electrolytes into ions. Once that is completed we cross off any reoccurring ions. That leaves us with our complete net ionic.
I also recommend you check out Wayne Breslyn on Yt. He is so helpful with equations like these.
In large doses it stops cells using oxygen causing these cells to die. So in a small amount it would not kill you. So lets say cyanide is inside the body it would kill off all the cells and your body would not be able to function causing death