Answer:
0.583M
Explanation:
M = CV
C is concentration in grams.
V is the volume.
Remember to convert mL to Litres.
Given data:
Concentration of stock solution which is the initial solution = M1 = 1.00 * 10^3 mg/L
Concentration of prepared solution i.e final solution = M2 = 6.250 mg/L
Volume of final solution, V2 = 5.000 * 10^2 ml
To determine:
The initial volume i.e. volume of the stock solution required = V1
Calculation:
Use the relation
M1V1 = M2V2
V1 = M2V2/M1 = 6.250 mg.L-1 * 5.000*10^2 ml/1.00 * 10^3 mg.L-1
V1 = 3.125 *10^3 ml
The volume of stock solution required is 3.125 *10^3 ml
The last number number is the estimating digit which is the four at the very end.
Answer:
= 10000000000000 Nanoliters
Explanation:
1.0 x (10^4) L =
10 000 L
10 000L converted into Nanoliters
= 10000000000000 Nanoliters
Hope this helps
Answer:
23.2 kJ of energy are released by the reaction.
Explanation:
Hello there!
In this case, according to the given information, it turns out firstly necessary for us to calculate the moles of both tin and nitrogen and the produced moles of Sn3N4 product by each reactant as shown below:
Thus, since 13.1 grams of tin produce the fewest moles of Sn3N4 product, we infer tin is the limiting reactant, and the correct produced energy, due to this reaction is:
Regards!