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Pachacha [2.7K]
3 years ago
11

Calcium metal reacts with a potassium chloride solution to form calcium chloride and potassium ions. Classify this reaction. Ca(

s) + 2KCl(aq) → CaCl2(s) + 2K+(aq)
Physics
1 answer:
Scilla [17]3 years ago
8 0
The given reaction above is an example of <em>single replacement reaction. </em>This is a certain type of reaction in which an element of a compound is replaced by a free element. In this case, chlorine (Cl) is replaced by calcium (Ca). 
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A skateboarder travels on a horizontal surface with an initial velocity of 4.0 m/s toward the south and a constant acceleration
Alenkinab [10]

Answer:

a) 0.32 m b) -2.4 m c) 1.08 m/s d) -4 m/s

Explanation:

a)

  • As the x and y axes (as chosen) are perpendicular each other, the movements along these axes are independent each other.
  • This means that we can use the kinematic equations for displacements along both axes.
  • In the x direction, as the only initial velocity is in the south direction (-y axis), the skateboarder is at rest, so we can write:

        x =\frac{1}{2}*a*t^{2} (1)

  • In the y-direction, as no acceleration is acting on the skateboarder, we can write  the following displacement equation:

        y = v_{0y} * t  (2)

  • For t = 0.6s, replacing by the givens, we get the position (displacement from the origin) on the x-axis, as follows:

       x =\frac{1}{2}*a*t^{2} =\frac{1}{2} * 1.8 m/s2*(0.6s)^{2}\\ x = 0.32 m

b)

  • From (2) we can get the position on the y-axis (displacement from the origin) as follows:

        y = v_{0y} * t  =  -4 m/s * 0.6 s = -2.4 m

c)

  • In the x- direction, we can find the component of the velocity along this direction, as follows:

        v_{fx} = a*t

  • Replacing by the values, we have:

        v_{fx} = a*t = 1.8 m/s2 * 0.6 s = 1.08 m/s

d)

  • As the skateboarder moves along the y-axis at a constant speed equal to her initial velocity, we  have:

        vfy = voy = -4 m/s

8 0
4 years ago
Who won the Battle of Barren Hill?
Serga [27]
The british won the Battle of Barren Hill :)
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3 years ago
How is static electricity different from electric current
Sindrei [870]

Answer:

1. Static electricity is caused by the build up of electrical charges on the surface of objects, while current electricity is a phenomenon from the flow of electrons along a conductor.

Explanation:

8 0
4 years ago
A worker with spikes on his shoes pulls on rope that is attached to a box that is resting on a flat, frictionless frozen lake. T
earnstyle [38]

Answer:

a

The free body diagram is shown on the first uploaded image

b

The tension on the rope is  T=39.16 \ N  

Explanation:

From the  question we are told that

    The mass of the box is  m

    The tension on the box is  T

     The angle at which it is pulled is  \theta =  40^o

     The force produced by the strong head wind is Fw =  30 \ N

At equilibrium the net force acting on the block along the horizontal axis is zero i.e

     Tcos \theta -F_w = 0

substituting values

     Tcos (40) -30 = 0

     Tcos (40)  = 30

     T(0.76604))  = 30

     T=39.16 \ N      

5 0
3 years ago
A basketball is tossed upwards with a speed of 5.0\,\dfrac{\text m}{\text s}5.0
xeze [42]
<h2>Answer:</h2>

<em>Hey,</em>

<h3><u>QUESTION)</u></h3>
  • v0 = 5 m/s

The ball is only subject to its own weight, so according to Newton's first law, there is :

\sum\overrightarrow{F_{ext}} = m \times \vec{a} \\&#10;\vec{P} = m \times \vec{a} \\&#10;m \times \vec{g} = m \times \vec{a} \\&#10; \vec{g} = \vec{a} \\&#10;\vec{a}\left(\begin{array}{c}a_x=0&a_y=-g\end{array}\right)\\&#10;

\text{Let's find the primitive of the acceleration vector}\\&#10;\vec{v}\left(\begin{array}{c}v_x= v_0 \times sin(\theta) & v_y=-gt + v_0 \times sin(\theta)\end{array}\right)\\&#10;\text{Let's find the primitive of the speed vector}\\&#10;\overrightarrow{OM}\left(\begin{array}{c} x= v_0 \times sin(\theta) \times t & y=-\frac{1}{2} gt^2 + v_0 \times sin(\theta)\times t\end{array}\right)\\&#10;

\text{At maximum altitude, the y-axis velocity is zero such that}\\&#10;v_y = 0 \Longleftrightarrow 0=-gt + v_0 \times sin(\theta) \Longleftrightarrow t = \frac{v_0\times sin(\theta)}{g} \ (1)\\&#10;\text{So this time t corresponds to the moment when the ball t reaches the top.}\\\\

Thus, knowing the theta value, we can find the maximum altitude by replacing t in the equation for y with the expression above.

4 0
2 years ago
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