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miss Akunina [59]
4 years ago
12

Two identical isolated conducting spheres are picked for an experiment. Only one of them is charged. If the spheres are now brie

fly brought into contact and then separated by a small distance, the two spheres would experience
A) a force of repulsion, because they are like-charged.
B) a force of attraction, because they are oppositely charged.
C) no force, because charges are not transferred by mere contact.
D) no force, because the distance separating the spheres needs to be large.
Physics
2 answers:
iren [92.7K]4 years ago
7 0

Answer:

A) a force of repulsion, because they are like-charged.

Explanation:

when the charged sphere is made in contact with the uncharged sphere some of the charges from will flow from the charged sphere to an uncharged sphere thus both become like charged therefore they repel each other.

vagabundo [1.1K]4 years ago
4 0

Answer:

A) a force of repulsion, because they are like-charged.

Explanation:

when the charged sphere is made in contact with the uncharged sphere some of the charges from will flow from the charged sphere to an uncharged sphere thus both become like charged therefore they repel each other.

Read more on Brainly.com - brainly.com/question/14190676#readmore

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Answer:

The answer to your question is

Explanation:

Data

mass = 0.5kg

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Formula

                        Q = mCp(T2 - T1)

                         T2 = T1 + Q/mCp    

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                        T2 = 35 - 63000/2092

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ε = Emissivity

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Since, emissivity and emissive power are constant.

Therefore,

P = σεA₁T₁⁴   ----------- equation 1

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Since, emissivity and emissive power are constant.

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A₂ = Surface Area of Bulb 2

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1 = A₁(3000)²/A₂(2000)²

A₁/A₂ = (2000)²/(3000)²

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